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dimulka [17.4K]
3 years ago
13

The weights of dogs at a kennel are Normally distributed with a mean of 18 pounds and a standard deviation of 3.5 pounds.In whic

h percentile is a dog who weighs 25 pounds?
Mathematics
2 answers:
saveliy_v [14]3 years ago
4 0

Answer:

97.5th percentile

This is the right answer edge 2020

Step-by-step explanation:

Ierofanga [76]3 years ago
3 0

Answer:

P(x=25)=P(z=2)=0.9972 or 99.72%

Step-by-step explanation:

Mean = 18 pounds

Standard Deviation = 3.5 pounds

x= 25

We need to find P(x=25)

First, we need to find z-score using formula: z-score=\frac{x-\mu}{\sigma}

Finding z-score when x=25

z-score=\frac{x-\mu}{\sigma}\\z-score=\frac{25-18}{3.5}\\z-score=2

So, we need to find P(z=2)=P(x=25)

Looking at z-score table we can find P(z=2)

P(z=2)=0.9972 or 99.72%

So, P(z=2)=0.9972 or 99.72%

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Step-by-step explanation:

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