Answer:
g/(b+ g)
Step-by-step explanation:
I have attached the solution below.
<h2><u>Part A:</u></h2>
Let's denote no of seats in first row with r1 , second row with r2.....and so on.
r1=5
Since next row will have 10 additional row each time when we move to next row,
So,
r2=5+10=15
r3=15+10=25
<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>
r1=5=5+0=5+0×10=5+(1-1)×10
r2=15=5+10=5+(2-1)×10
r3=25=5+20=5+(3-1)×10
<u>So for nth row,</u>
rn=5+(n-1)×10
Since 5=r1 and 10=common difference (d)
rn=r1+(n-1)d
Since 'a' is a convention term for 1st term,
<h3>
<u>⇒</u><u>rn=a+(n-1)d</u></h3>
which is an explicit formula to find no of seats in any given row.
<h2><u>Part B:</u></h2>
Using above explicit formula, we can calculate no of seats in 7th row,
r7=5+(7-1)×10
r7=5+(7-1)×10 =5+6×10
r7=5+(7-1)×10 =5+6×10 =65
which is the no of seats in 7th row.
Answer:
There was 62.23% change in radius as the ion formed.
Step-by-step explanation:
Given
Radius of Aluminium 
atom = 143 pm
Radius of Aluminium 
atom = 54 pm
Change is the radius = Radius of Aluminium atom - Radius of Aluminium atom = 143 -54 = 89
Now to find % Change is the radius we will divide Change is the radius by Radius of Aluminium atom and multiply by 100 we get
% Change is the radius = 
Hence there was 62.23% change in radius as the ion formed.
Answer where
Step-by-step explanation:
Answer:
a simplified fraction would be 4/10 but not simplified would be 40/100
Step-by-step explanation:
