Answer:
The correct answer is option d.
Explanation:
The production of Acetyl-CoA takes place by the dissociation of both carbohydrates and lipids in the process of glycolysis and beta-oxidation. It then moves into the TCA cycle in the mitochondria and combines with oxaloacetate to give rise to citrate.
In the given case, no labeling will be found in the acetyl-CoA. The labeled C3 and C4 carbon of glucose signify the carboxyl carbon of pyruvate. In the succeeding reactions of the transformation of pyruvate to acetyl-CoA, the carboxyl carbon gets lost in the form of carbon dioxide. Thus, acetyl-CoA does not comprise any labeled C3 and C4 of glucose.
300 BC by Greek philosophers
The answer is A) Carbon
Hope this helps.
Answer:
Option-A
Explanation:
Pentose phosphate pathway is the alternative pathway taking place in both eukaryotes and prokaryotes parallel to the glycolysis.
The pentose phosphate pathway forms the electron carriers called NADPH and the ribose-5 phosphate.
The NADPH is formed in large amounts through this pathway which contains a very high amount of energy. NADPH can donate its hydride ions, therefore, it can be involved in the reaction where it can donate energy in the form of hydrogen and electron.
The NADPH is therefore involved in the formation of reducing biosynthetic pathways like fatty acid synthesis, cholesterol synthesis, and bile acid synthesis.
Thus, Option-A is the correct answer.
Hello There!
It was a Greek astronomer called Aristarchus of Samos.
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