Question

A girl takes her dog for a walk on a sunny beach. Find the force of gravity between the 45-kg girl and her 11-kg dog when they are separated by a distance of 2.00m

Answer 1

The gravitational force acting between them is $8.25*10^-^9N$

Data given;

• M1 = 45kg
• M2 = 11kg
• r = 2.0m
• G = $6.67*10^-^1^1m^3kg^-^1s^-^1$

To solve this question, we need to apply gravitational force or energy formula.

Gravitational Force

This states that the force of attraction between two bodies is equal to the product of their bodies and inversely proportional to the square of their distance apart.

Mathematically;

$F = \frac{GM_1M_2}{r^2}$

let's substitute the values and solve

$F = \frac{Gm_1m_2}{r^2}\\F = \frac{6.67*10^-^1^1 * 45 * 11}{2^2}\\F = 8.25*10^-^9N$

The force of gravity acting between them is $8.25*10^-^9N$

Learn more on gravitational force here;

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