1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
WITCHER [35]
3 years ago
11

an athlete in a hammer-throw event swings a 7.0-kilogram hammer in a horizontal circle at a constant speed of 12 meters per seco

nd. The radius of the hammer's path is 2.0 meters.
Physics
1 answer:
Semenov [28]3 years ago
6 0

Answer:

ac = 72 m/s²

Fc = 504 N

Explanation:

We can find the centripetal acceleration of the hammer by using the following formula:

a_c = \frac{v^2}{r}

where,

ac = centripetal acceleration = ?

v = constant speed = 12 m/s

r = radius = 2 m

Therefore,

a_c = \frac{(12\ m/s)^2}{2\ m}

<u>ac = 72 m/s²</u>

<u></u>

Now, the centripetal force applied by the athlete on the hammer will be:

F_c = ma_c\\F_c = (7\ kg)(72\ m/s^2)

<u>Fc = 504 N</u>

You might be interested in
Three capacitors with capacitances:
mr_godi [17]

Answer:

A. 80.0microColoumbs

B.120.0 microcoloumbs

C.37.3v

Explanation:

See attached file

6 0
4 years ago
A boy on the edge of a vertical cliff 20-m high throws a stone horizontally outwards with a speed of 20 m/s. It strikes the grou
Komok [63]

Answer:

Horizontal distance from the foot of the cliff is 40 m

Explanation:

Given :

Speed of stone v = 20\frac{m}{s}

Vertical distance d = 20 m

Gravitational acceleration g = 10 \frac{m}{s^{2} }

From the kinematics equation,

  d = v_{o} t + \frac{1}{2} at^{2}

Where v_{o} = initial velocity ( v_{o} = 0 )

So time take to fall down,

  t = \sqrt{\frac{2d}{a} }

  t = \sqrt{4}

  t = 2 sec

Now find horizontal distance travel by stone,

 x = vt

 x = 20 \times 2

 x = 40 m

Therefore, the horizontal distance travel by stone is 40 m

3 0
3 years ago
A ball is thrown vertically upwards at 19.6 m/s. For its complete trip (up and back down to the starting position), its average
stira [4]

When the ball reaches its original position, it will have the same speed (but would be traveling in the opposite direction). So the average speed is

\dfrac{19.6\,\frac{\mathrm m}{\mathrm s}-19.6\,\frac{\mathrm m}{\mathrm s}}{\Delta t}=0

regardless of how long the ball was in the air.

5 0
3 years ago
Two positive point charges, each of which has a charge of 2.5 × 10−9 C, are located at y = + 0.50m and y = − 0.50m. Find the mag
nadya68 [22]

Answer:

F = 147,78*10⁻⁹ [N]

Explanation:

By symmetry the Fy components of the forces acting on charge in point x = 0,7 m canceled each other, and the total force will be twice Fx ( Fx is x axis component of one of the forces .

The angle β  ( angle between the line running through one of the charges in y axis and the charge in x axis) is

tan β  =  0,5/0,7

tan β  = 0,7142    then   β = arctan 0,7142      ⇒   β = 35 ⁰

cos  β = 0,81

d = √ (0,5)²  +  (0,7)²       d1stance between charges

d = √0,25 + 0,49

d =  √0,74  m

d = 0,86  m

Now Foce between two charges  is:

F  = K* q₁*q₂/ d²      (1)

Where  K  = 9*10⁹ N*m²/C²

q₁  =  2,5* 10⁻⁹C

q₂  = 3,0*10⁻⁹C

d²  = 0,74 m²

Plugging these values in (1)

F  =  9*10⁹* 2,5* 10⁻⁹*3,0*10⁻⁹ / 0,74       [N*m²/C²]*C*C/m²

F = 91,21 * 10⁻⁹   [N]

And  Fx  =  F*cos  β

Fx  =  91,21 * 10⁻⁹ *0,81

Fx =73,89*10⁻⁹  [N]

Then total force acting on charge located at x = 0,7 m is:

F = 2* Fx

F = 2*73,89*10⁻⁹  [N]

F = 147,78*10⁻⁹ [N]

8 0
3 years ago
Help quick<br> p;leaseeeeeeeeeeee its about direction and magnitude
KonstantinChe [14]

Explanation:

The net force of each square is the combination of the forces in each direction. The direction is the... direction the square would go in due to the net force. The magnitude of the net force is how large it is. So if you had a force pushing 2N to the left and 1N to the right, then the net force would be 1N to the left; because the two oppose eachother. If they were going in the same direction, then they'd add to each other. And perpendicular net forces (like one pushing up and another pushing left) can create net forces in diagonal directions.

I'm not going to do all of these for you because they're basically all the same thing and it's good practice for you anyway. But I'll do the first three just so you can get the idea:

1. The net force's magnitude is 4N and it's direction is to the right.

2. The net force's magnitude is 4N and it's direction is to the left.

3. The net force's magnitude is 0N and it has no direction because they are equal forces acting in opposite directions.

7 0
3 years ago
Other questions:
  • This boy uses a force to lift a heavy rock. (He is carrying it.) What can the boy do if he wants to lift the same rock more quic
    11·2 answers
  • State the law of conservation of energy
    9·2 answers
  • A machine can never be 100% efficient because some work is always lost due to .
    5·2 answers
  • The fulcrum is between the effort and the load
    14·1 answer
  • Ice has a density of 0.920 g/cm3. An ice cubes mass is 100 g. What is its volume?
    5·1 answer
  • If there were no air resistance, how long would it take a free-falling skydiver to fall from a plane at 3000 m to an altitude of
    6·1 answer
  • A book sitting on a shelf has gravitational potential energy. true or false
    13·2 answers
  • According to the Law of Reflection, the angle of incidence
    10·1 answer
  • What is the difference between primary cells and secondary cells?​
    11·2 answers
  • Convert 60 kg to mg using the method of dimensional analysis
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!