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3 years ago

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A tall cylinder contains 20 cm of water. Oil is carefully poured into the cylinder, where it floats on top of the water, until t

he total liquid depth is 40 cm.
Required:
What is the gauge pressure at the bottom of the cylinder?

1 answer:

Zanzabum3 years ago

3 0

Answer:

Pressure, P = 3724 Pa

Explanation:

Given that,

Depth of water, $h_w=20\ cm =0.2\ m$

Depth of oil, $h_o=40-20=20\ cm=0.2\ m$

The density of water, $d_w=1000\ kg/m^3$

The densinty of oil, $d_o=900\ kg/m^3$

We need to find the gauge pressure at the bottom of the cylinder. So, total pressure is equal to :

$P=d_wgh_w+d_ogh_o\\\\P=(d_wh_w+d_oh_o)g\\\\P=(1000\times 0.2+900\times 0.2)\times 9.8\\\\P=3724\ Pa$

So, the gauge pressure at the bottom of the cylinder is 3724 Pa.

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Question Parameters:

A 1. 0 μf capacitor is being charged by a 9. 0 v battery through a 10 mω resistor.

at

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Generally, the equation for the Voltage is mathematically given as

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Therefore

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For t=20s

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V2=4.323v

Therefore, the values of voltages at the various times are

t=0.476v
t=1.967v
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Complete Question

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