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2 years ago

What is the product? (x 3)(2 x minus 1) 2 x squared minus 3 2 x squared 6 x 2 x squared 5 x minus 3 2 x squared 6 x minus 3.

Mathematics

1 answer:

prohojiy [21]2 years ago

5 0

The product of the function is 2x^2+ 5x - 3

We are to find the product of the functions x + 3 and 2x -1

let f(x) = x+ 3

g(x) = 2x - 1

Taking the product:

f(x)g(x) = (x+3)(2x -1)

f(x)g(x) = x(2x) - x(1) + 3(2x) + 3(-1)

f(x)g(x) = 2x^2 - x + 6x - 3

f(x)g(x) = 2x^2+ 5x - 3

Hence the product of the function is 2x^2+ 5x - 3

Learn more on product of functions here: brainly.com/question/25638609

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ivanzaharov [21]

2 m/s²

Step-by-step explanation:

Step 1:

Let the initial velocity be 0 m/s and the final velocity be 8 m/s and the time traveled is 4 s.

From the basic science,

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4 0

3 years ago

Find the nth degree polynomial function with real coefficients satisfying the given conditions.

RUDIKE [14]

$\bf (x+1)(x-3)(x-2-4i)(x-2+4i)
\\\\
\textit{now, let's take a peek at }(x-2-4i)(x-2+4i)\\
\textit{and recall our }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
(x-2-4i)(x-2+4i)\implies [(x-2)-(4i)][(x-2)+(4i)]
\\\\\
[(x-2)^2-(4i)^2]\implies [(x^2-2x+4)-(4^2\boxed{i^2})]
\\\\\
[(x^2-2x+4)-(16\cdot \boxed{-1})]\implies [(x^2-2x+4)+16]
\\\\
(x^2-2x+20)\\\\
-----------------------------$

$\bf thus
\\\\

\begin{array}{llll}
(x+1)(x-3)\\(x-2-4i)(x-2+4i)
\end{array}\implies (x+1)(x-3)(x^2-2x+20)
\\\\\\
(x^2-2x-3)(x^2-2x+20)\implies 
\begin{array}{llll}
x^4-2x^3+20x^2-2x^3\\+4x^2-40x+3x^2-6x+60
\end{array}
\\\\\\
x^4-4x^3+27x^2-46x+60$

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2 years ago

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labwork [276]

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The product fraction should be easily simplified using A and B to get the original fraction.

<em>In the case of your fraction </em> $\frac{7}{10}$ you will need to find a fraction which is a product of this: $\frac{7\timesA}{10\timesB},A=B$

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