Malachite green elutes faster from the column than crystal violet so malachite green is the _________ dye.

Chemistry

1 answer:

yawa3891 [41]3 years ago

5 0

Answer:

Malachite green is prepared by the condensation of benzaldehyde and dimethylaniline to give leuco malachite green (LMG): Second, this colorless leuco compound, a relative of triphenylmethane, is oxidized to the cation that is MG: C6H5CH(C6H4N(CH3)2)2 + HCl + 1⁄2 O2 → [C6H5C(C6H4N(CH3)2)2]Cl + H2O.

Explanation:

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Setler [38]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

CH4 + 202 → CO2 + 2H2O<br> How many grams of O2 needed to react with 2 moles of CH4?

PtichkaEL [24]

<h3>Answer:</h3>

100 g O₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O

[Given] 2 mol CH₄

[Solve] x g O₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol CH₄ → 2 mol O₂

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

<u>Step 3: Stoichiometry</u>

Set up conversion: $\displaystyle 2 \ mol \ CH_4(\frac{2 \ mol \ O_2}{1 \ mol \ CH_4})(\frac{32.00 \ g \ O_2}{1 \ mol \ O_2})$
Multiply/Divide: $\displaystyle 128 \ g \ O_2$