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Maksim231197 [3]
3 years ago
15

7 inches and 23.1 inches, what is the scale factor for the set?

Mathematics
1 answer:
Semenov [28]3 years ago
4 0
Well, to find the scale from 7 to 23.1, simply divide 23.1 by 7.
The scale factor for the set is 3.3.
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Does anyone know how to do this?? steps are helpful but not necessary
aniked [119]

Answer:

C.  \frac{2(x+16)}{x+4}

Step-by-step explanation:

We want fg of x, so first we have to multiply f(x) times g(x).

\frac{x+16}{x} * \frac{2x}{x+4}

\frac{(x+16)2x}{x(x+4)}

\frac{2x^{2}+32x}{x^{2}+4x}

We can cancel out an x from every term.

\frac{2x+32}{x+4}

Let's rewind a little to get this into one of the answer choices.

\frac{2(x+16)}{x+4} is our answer.

6 0
3 years ago
PLEASE HELP !!!!!!!!!!! WILL MARK BRIANLIEST !!!!!!!!!!!!!
Igoryamba

Answer:

3:2

Step-by-step explanation:

I'd say 3:2 because when you divide 45/30, you get 3/2, which is the same as 3:2. Hope this helps!

4 0
3 years ago
Read 2 more answers
Which of the following equations could be used to find the value of 3,550 ÷ 25?
fiasKO [112]

Answer:

<em>A is correct answer</em>

Step-by-step explanation:

(3000 + 500 + 50) \div 25 \\

(3550) \div 25

=  =  > 3550 \div 25

Thanks

Don't forget to tell the name of your country.

8 0
2 years ago
A calculator is required to obtain the final answer on this question. A solid metal sphere at room temperature 20oC is dropped i
yKpoI14uk [10]

Answer:

T = 47.1875°C

Step-by-step explanation:

Given:

Surrounding temp, Ts = 100°C

Initial Temperature ,T0= 20°C

Increase in temperature = 15°C

Final temperature, T = 20 + 15 = 35°C

Time, t = 9 seconds

Let's take Newton's law of cooling:

T - Ts = (T_0 - Ts)e^k^t

We'll solve for k

35 - 100 = (20 - 100)e^9^k

-65 = (-80)e^9^k

Divide both sides by -5

13 = (16)e^9^k

9k = ln (\frac{13}{16})

k = \frac{1}{9} ln (\frac{13}{16})

k = -0.02307104053

Let's now find the temperature of the ball after 18 seconds in boiling water.

Use the Newton's equation again:

T - Ts = (T_0 - Ts)e^k^t

T - 100 = (20 - 100)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8

T - 100 = (-80)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8

T - 100= -52.8125

T = 100 - 52.8125

T = 47.1875°C

Temperature of the ball after 18 seconds in boiling water is 47.1875°C

5 0
3 years ago
Ninety-eight and seventy-three hundredths which place are tens , ones , tenths , hundredths?
Naily [24]
8 is the hundreds, 7 in the tens, and 3 in the ones
4 0
2 years ago
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