Answer:
Brainliest!!!
Step-by-step explanation:
see picture
Answer:
B
Step-by-step explanation:
The other ones are false claims
Answer:
-2
Step-by-step explanation:
line crosses the y- coordinate (0,-2)
Answer:
a) ![z= \frac{34-34}{2.5}= 0](https://tex.z-dn.net/?f=%20z%3D%20%5Cfrac%7B34-34%7D%7B2.5%7D%3D%200)
![z= \frac{39-34}{2.5}= 2](https://tex.z-dn.net/?f=%20z%3D%20%5Cfrac%7B39-34%7D%7B2.5%7D%3D%202)
And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %
b) ![P(X](https://tex.z-dn.net/?f=%20P%28X%3C31.5%29%20)
![z= \frac{31.5-34}{2.5}= -1](https://tex.z-dn.net/?f=%20z%3D%20%5Cfrac%7B31.5-34%7D%7B2.5%7D%3D%20-1)
So one deviation below the mean we have: (100-68)/2 = 16%
c) ![z= \frac{29-34}{2.5}= -2](https://tex.z-dn.net/?f=%20z%3D%20%5Cfrac%7B29-34%7D%7B2.5%7D%3D%20-2)
![z= \frac{36.5-34}{2.5}= 1](https://tex.z-dn.net/?f=%20z%3D%20%5Cfrac%7B36.5-34%7D%7B2.5%7D%3D%201)
For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%
Step-by-step explanation:
For this case we have a random variable with the following parameters:
![X \sim N(\mu = 34, \sigma=2.5)](https://tex.z-dn.net/?f=%20X%20%5Csim%20N%28%5Cmu%20%3D%2034%2C%20%5Csigma%3D2.5%29)
From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.
We want to find the following probability:
![P(34 < X](https://tex.z-dn.net/?f=%20P%2834%20%3C%20X%3C39%29)
We can find the number of deviation from the mean with the z score formula:
![z= \frac{X -\mu}{\sigma}](https://tex.z-dn.net/?f=%20z%3D%20%5Cfrac%7BX%20-%5Cmu%7D%7B%5Csigma%7D)
And replacing we got
![z= \frac{34-34}{2.5}= 0](https://tex.z-dn.net/?f=%20z%3D%20%5Cfrac%7B34-34%7D%7B2.5%7D%3D%200)
![z= \frac{39-34}{2.5}= 2](https://tex.z-dn.net/?f=%20z%3D%20%5Cfrac%7B39-34%7D%7B2.5%7D%3D%202)
And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %
For the second case:
![P(X](https://tex.z-dn.net/?f=%20P%28X%3C31.5%29%20)
![z= \frac{31.5-34}{2.5}= -1](https://tex.z-dn.net/?f=%20z%3D%20%5Cfrac%7B31.5-34%7D%7B2.5%7D%3D%20-1)
So one deviation below the mean we have: (100-68)/2 = 16%
For the third case:
![P(29 < X](https://tex.z-dn.net/?f=%20P%2829%20%3C%20X%3C36.5%29)
And replacing we got:
![z= \frac{29-34}{2.5}= -2](https://tex.z-dn.net/?f=%20z%3D%20%5Cfrac%7B29-34%7D%7B2.5%7D%3D%20-2)
![z= \frac{36.5-34}{2.5}= 1](https://tex.z-dn.net/?f=%20z%3D%20%5Cfrac%7B36.5-34%7D%7B2.5%7D%3D%201)
For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%