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koban [17]
3 years ago
5

What is the answer to this question

Mathematics
1 answer:
zimovet [89]3 years ago
3 0

Answer:

   n^10/(144m^4)

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

  a^-b = 1/a^b

  (ab)^c = (a^c)(b^c)

__

Using these rules, we can simplify the given expression as follows:

  \left(\dfrac{3m^{-5}n^2}{4m^{-2}n^0}\right)^2\left(\dfrac{mn^4}{9n}\right)^2=\left(\dfrac{3}{4}m^{-5(-(-2))}n^{2-0}\right)^2\left(\dfrac{1}{9}mn^{4-1}\right)^2\\\\=\left(\dfrac{3n^2}{4m^3}\right)^2\left(\dfrac{m^3}{9}\right)^2=\dfrac{3^2n^4}{4^2m^6}\cdot\dfrac{m^2n^6}{9^2}=\boxed{\dfrac{n^{10}}{144m^4}}

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Step-by-step explanation:

Plug in the numbers for the x-value and solve the equation.

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Lunch break: In a recent survey of 655 working Americans ages 25-34, the average weekly amount spent on lunch was $43.5
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Using the Empirical Rule, it is found that:

  • a) Approximately 99.7% of the amounts are between $35.26 and $51.88.
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  • c) Approximately 68% of the amounts fall between $40.73 and $46.27.

------------

The Empirical Rule states that, in a <em>bell-shaped </em>distribution:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
  • Approximately 95% of the measures are within 2 standard deviations of the mean.
  • Approximately 99.7% of the measures are within 3 standard deviations of the mean.

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Item a:

43.5 - 3(2.77) = 35.26

43.5 + 3(2.77) = 51.88

Within <em>3 standard deviations of the mean</em>, thus, approximately 99.7%.

-----------

Item b:

43.5 - 2(2.77) = 38.03

43.5 + 2(2.77) = 49.11

Within 2<em> standard deviations of the mean</em>, thus, approximately 95%.

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Item c:

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43.5 - 2.77 = 40.73

43.5 + 2.77 = 46.27

Approximately 68% of the amounts fall between $40.73 and $46.27.

A similar problem is given at brainly.com/question/15967965

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