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3 years ago

Find a function of the form f(x) = a sin(bx − c) such that the graph of f matches the figure.

Mathematics

1 answer:

aliina [53]3 years ago

4 0

Answer:

y = 3sin(2x+pi)

Step-by-step explanation:

We know that a is equal to 3 because the distance from 3 to the midpoint 0 is 3

We also know that is a phase shift of pi/2 as that is where the new start of our sine function lands

We know there is a compression of 2 as our period has changed from 2pi to pi

So naturally we change pi/2 to pi since we put the 2 inside the parenthesis

Best of luck

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A= B + 3(4 - C) <br> B=5<br> C= 2<br> A=?

Trava [24]

Answer:

A = 11 i believe

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

\sqrt{2x^2+x+1}+\sqrt{x^2-x+1}=3x

djyliett [7]

X=1

Mark brainliest please

Hope this helps you

7 0

2 years ago

proszę o pomocy bardzo, lepej żeby było szybko, mam kartkówkę. Pytanie: wyznacz współrzędne i długość wektora AB jeżeli A(-3,-1)

IgorLugansk [536]

Answer:

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6 0

3 years ago

Find all degree solutions in the interval 0° ≤ θ < 360°. If rounding is necessary, round to the nearest tenth of a degree. Us

xenn [34]

Answer:

$\theta_{1} \approx 30.473^{\textdegree}$

$\theta_{2} \approx 120.473^{\textdegree}$

$\theta_{3} \approx 210.473^{\textdegree}$

$\theta_{4}\approx 300.473^{\textdegree}$

Step-by-step explanation:

The equation needs to be rearranged in terms of one trigonometric function:

$5\cdot \sin 2\theta - 9\cdot \cos 2\theta = 0$

$5\cdot \tan 2\theta - 9 = 0$

$5\cdot \tan 2\theta = 9$

$\tan 2\theta = \frac{9}{5}$

$\theta = \frac{1}{2}\cdot \tan^{-1} \left(\frac{9}{5} \right)$

The tangent function has positive values in the 1st and 3rd Quadrants. Then, the solutions are:

$\theta_{1} \approx 30.473^{\textdegree}$

$\theta_{2} \approx 120.473^{\textdegree}$

$\theta_{3} \approx 210.473^{\textdegree}$

$\theta_{4}\approx 300.473^{\textdegree}$

3 0

3 years ago

You and two friends buy snacks for a field trip. Using the

stepladder [879]

Answer:

13.15

Step-by-step explanation:

7 0

3 years ago