If you wanted to make the graph of y=3x+1 steeper which equation could you use
1 answer:
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Answer:
Step-by-step explanation:
The first thing you have to do is look at the mother curve. That curve is y = 1/x
It becomes undefined at x = 0 (I will show both curves below).
That is not what has been given. The graph you have been given becomes undefined at x = - 1 , so the equation of the curve (so far) y = 1/(x + 1)
Now we have to worry about the y intercept. When x = 0, y = 4. That can be accomplished in two ways
A. y = 4/(x + 1) or
B. y = 2/(x + 1) + 2 or
C. y = 1/(x + 1) + 3
All three of these will give a value of y = 4 when x = 0. But you have 1 problem left. What happens as x goes to say 5.
The value of A will give y = 4/(5 + 1)=4/6 = 2/3. Which does not work.
The value of C will give y = 1/(5 + 1) + 3 which gives 3 1/5 which also does not work.
Only B works. y = 2/(5+1) + 2 = 2/6 + 2 = 2 1/3 which is a little above the horizontal asymptote.
Red: y = 1/x
Blue: y = 2/(x + 1) + 2
The value at the end is never going to change. y will always be just a bit
