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Ulleksa [173]
2 years ago
14

Please answer me!!!! ​

Chemistry
1 answer:
Dmitry [639]2 years ago
4 0

Answer:

1) Starting boiling point is 100°C

Explanation: Boiling point is a constant temperature. At 10 minutes, substance L boils constantly at 100°C till 14 minutes.

2) The temperature of substance L steadily increases from 0 to 8 minutes. Then it is constant from 10 to 14 minutes.

3). Substance L is a pure substance. Substance L is pure water because pure water boils at 100°C

{}

e):

Substance L is Water

Reason: Substance L has boiling point of 100°C as well as water

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olga2289 [7]
They are both true glad i could help
5 0
3 years ago
Which of the following is a possible Noble gas notation?
denis23 [38]

C.) [Ar] 4s23d104p2

i just took the quiz and this was the correct answer :-)

5 0
3 years ago
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Number 14 please help.. chemistry
Zolol [24]

Taking into account the definition of density, the mass of a substance with a volume of 150 cm³ and a density of 1.5 \frac{g}{cm^{3} }  is 225 grams.

<h3>What is density</h3>

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

<h3>Mass of the substance in this case</h3>

In this case, you know that:

  • Density= 1.5 \frac{g}{cm^{3} }
  • Volume= 150 cm³

Replacing in the definition of density:

1.5 \frac{g}{cm^{3} } =\frac{mass}{150 cm^{3} }

Solving:

mass= 1.5 \frac{g}{cm^{3} }  ×150 cm³

<u><em>mass= 225 g</em></u>

In summary, the mass of a substance with a volume of 150 cm³ and a density of 1.5 \frac{g}{cm^{3} }  is 225 grams.

Learn more about density:

brainly.com/question/952755

brainly.com/question/1462554

#SPJ1

7 0
2 years ago
What is the minimum amount of 6.9 M H2SO4 necessary to produce 27.8 g of H2 (g) according to the following reaction? 2Al(s)+3H2S
Arte-miy333 [17]

Answer : The minimum amount of 6.9 M H_2SO_4 needed is, 2.0 L

Explanation :

The given chemical reaction is:

2Al(s)+3H_2SO_4(aq)\rightarrow Al_2(SO_4)_3(aq)+3H_2(g)

First we have to calculate the moles of H_2

\text{Moles of }H_2=\frac{\text{Mass of }H_2}{\text{Molar mass of }H_2}

Molar mass of H_2 = 2 g/mol

\text{Moles of }H_2=\frac{27.8g}{2g/mol}=13.9mol

Now we have to calculate the moles of H_2SO_4

From the balanced chemical reaction we conclude that,

As, 3 moles of H_2 produced from 3 moles of H_2SO_4

So, 13.9 moles of H_2 produced from 13.9 moles of H_2SO_4

Now we have to calculate the mass of H_2SO_4

\text{Concentration of }H_2SO_4=\frac{\text{Moles of }H_2SO_4}{\text{Volume of }H_2SO_4}

6.9M=\frac{13.9mol}{\text{Volume of }H_2SO_4}

\text{Volume of }H_2SO_4=2.0L

Thus, the minimum amount of 6.9 M H_2SO_4 needed is, 2.0 L

3 0
4 years ago
In the normal phase separation column, a solute was found to have retention time of 29.1 min, and an unretained sample had a ret
Karo-lina-s [1.5K]

Answer:

See explaination

Explanation:

Please kindly check attachment for detailed andd step by step solution of the given problem.

4 0
3 years ago
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