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DIA [1.3K]
2 years ago
9

Someone add me need friendsss :)) (ps we can help each other on our homework!!)

Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
7 0

Answer:

ok im sending you a freind request now

Step-by-step explanation:

i hope you arent higher than highschool level work tho

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Converse Perpendicular Transversal Theorem.
If two lines are perpendicular to the same line, then the lines are parallel.
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A week before the election, 1,500 people were asked who they planned to vote for. 45% said they planned to vote for Candidate X.
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CAN SOMEONE PLS HELP MEEEEEEE
k0ka [10]

9514 1404 393

Answer:

  1. 6x +y = -6
  2. 6x -y = 8
  3. 5x +y = 13

Step-by-step explanation:

To rewrite these equations from point-slope form to standard form, you can do the following:

  • eliminate parentheses
  • subtract the x-term
  • subtract the constant on the left
  • if the coefficient of x is negative, multiply by -1

Of course, any operation you do must be done <em>to both sides of the equation</em>.

__

1. y -6 = -6(x +2)

  y -6 = -6x -12 . . . . . eliminate parentheses

  6x +y -6 = -12 . . . . . add 6x

  6x +y = -6 . . . . . . . . add 6

__

2. y +2 = 6(x -1)

  y +2 = 6x -6

  -6x +y +2 = -6

  -6x +y = -8

  6x -y = 8 . . . . . . . . multiply by -1

__

3. y -3 = -5(x -2)

  y -3 = -5x +10

  5x +y -3 = 10

  5x +y = 13

_____

<em>Additional comment</em>

The "standard form" of a linear equation is ax+by=c for integers a, b, c. The leading coefficient (generally, 'a') should be positive, and all coefficients should be mutually prime (have no common factors). That is why we multiply by -1 in problem 2.

7 0
3 years ago
Help me with 18 19 and 20 plz
Rzqust [24]
19: He multiplied instead of dividing which will make a totally incorrect answer
6 0
3 years ago
point b on the ground is 5 cm from point E at the entrance to Ollie's house. He is 1.8 m tall and is standing at Point D, below
enot [183]

Point B on the ground is 5 cm from point E at the entrance to Ollie's house.

Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.

The complete question is as follows:

Ollie has installed security lights on the side of his house that is activated by a  sensor. The sensor is located at point C directly above point D. The area covered by the sensor is shown by the shaded region enclosed by triangle ABC. The distance from A to B is 4.5 m, and the distance from B to C is 6m. Angle ACB is 15°.

The objective of this information is:

  • To find angle CAB and;
  • Find the distance Ollie is from the entrance to his house when he first activates the sensor.

The diagrammatic representation of the information given is shown in the image attached below.

Using  cosine rule to determine angle CAB, we have:

\mathbf{\dfrac{AB}{Sin \hat {ACB}} = \dfrac{BC}{Sin \hat {CAB}}= \dfrac{CA}{Sin \hat {ABC}}}

Here:

\mathbf{\dfrac{AB}{Sin \hat {ACB}} = \dfrac{BC}{Sin \hat {CAB}}}

\mathbf{\dfrac{4.5}{Sin \hat {15^0}} = \dfrac{6}{Sin \hat {CAB}}}

\mathbf{Sin \hat {CAB} = \dfrac{Sin 15 \times 6}{4.5}}

\mathbf{Sin \hat {CAB} = \dfrac{0.2588 \times 6}{4.5}}

\mathbf{Sin \hat {CAB} = 0.3451}

∠CAB = Sin⁻¹ (0.3451)

∠CAB = 20.19⁰

From the diagram attached;

  • assuming we have an imaginary position at the base of Ollie Standing point called point F when Ollie first activates the sensor;          

Then, we can say:

∠CBD = ∠GBF

∠GBF = (CAB + ACB)      

(because the exterior angles of a Δ is the sum of the two interior angles.

∠GBF = 15° + 20.19°

∠GBF = 35.19°

Using the trigonometric function for the tangent of an angle.

\mathbf{Tan \theta = \dfrac{GF}{BF}}

\mathbf{Tan \ 35.19  = \dfrac{1.8 \ m }{BF}}

\mathbf{BF  = \dfrac{1.8 \ m }{Tan \ 35.19}}

\mathbf{BF  = \dfrac{1.8 \ m }{0.7052}}

BF = 2.55 m

Finally, the distance of Ollie║FE║ from the entrance of his bouse is:

= 5 - 2.55 m

= 2.45 m

Therefore, we can conclude that Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.

Learn more about exterior angles here:

8 0
3 years ago
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