Question 1. It is graph 3 since the y-intercept in the equation is -2 and the y-intercept on the graph 3 is -2. It is also a quadratic function.
Question 2. It is graph two because the equation listed represents a quadratic function that is positive (graph opens up).
Question 3. It is graph 4 since the y-intercept is 2 and the only graph with that intercept is graph 4. Also, the equation represents a linear function.
Hope this helped :))
Answer:
(c) micrograms (µg)
Step-by-step explanation:
Answer:
-30/15 or -2
Step-by-step explanation:
2+8 = 10
3+2 = 5
14-2 = 12
4-1 = 3
10/5 - 12/3
(Find GCF)(GCF = 15)(5 times 3)
30/15 (10/5 times 3)
60/15 (12/3 times 5)
30/15 - 60/15 = -30/15 --> -2(simplified to 2)
Answer:
Sum = 140
Step-by-step explanation:
We find all the terms, we know that every consecutive term, we add 2 until we reach 23:
Sum = 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23
Sum = 140
The correct answer is: [B]: "4 " .
______________________________________
Explanation:
______________________________________
Refer to the table (provided within the actual question).
Note that the "inputs" ; or "x-values" ; are all listed in "chronological order" ; and are all "one (1) unit apart. and range from: "x = -3" to "x = 3" .
When "x = 0" ; the "output" ; or "f(x)" is "1/4" .
When "x = 1" ; the "output" ; or "f(x)" is: "1" .
_________________________________________________
So; the ratio of these two "outputs" is: "¼ : 1" ; or, write as:
" (¼) / 1 " ; and note that: " (¼) / 1 = (¼) ÷ 1 = ¼.
However; note that: "1/4" ; or "1:4" is NOT among the [answer choices given].
However, the ratio of the 2 (two) corresponding "outputs"; chronologically,
going from when "x = 1" ; to "x = 0" ; is: "1 : ¼" ; or; write as: "1 / (¼)" ;
And note that: "1 / (¼)" = " 1 ÷ (¼) " = 1 * (4/1) = 1 * 4 = "4" .
This corresponds to: Answer choice: [B]: "4<span>" .
</span>_________________________________________________
Let us further confirm that this answer is correct:
_________________________________________________
When x = 3; the "output" is: "16" .
When x = 2; the "output" is: "4" .
The ratio: "16/4 = ? 4 ? " ; → Yes!
_________________________________________________
When x = 2; the "output" is: "4" .
When x = 1; the "output" is: "1" .
The ratio: "4/1 = ? 4 ? " ; → Yes!
_________________________________________________
When x = 1; the "output" is: "1" .
When x = 0; the "output" is: "(¼)" .
The ratio: "1 / (¼) = ? 4 ? " ;
→ "1 / (¼)" = " 1 ÷ (¼) " = 1 * (4/1) = 1 * 4 = "4" . YES!
________________________________________________
When x = 0; the "output" is: "(¼)" .
When x = -1; the "output" is: "(¹/₁₆)" .
The ratio: "(¼) / (¹/₁₆) = ? 4 " ? ;
→ "(¼) / (¹/₁₆) = "(¼) ÷ (¹/₁₆) " = "(¼) * (¹⁶/₁) = (1*16) / (4*1) = 16/4 = "4" . Yes!
________________________________________________________
When x = -1; the "output" is: "(¹/₁₆)" .
When x = -2; the "output" is: "(¹/₆₄)" .
The ratio: "(¹/₁₆) / (¹/₆₄) = ? 4 " ? ;
→ "(¹/₁₆) / (¹/₆₄) = "(¹/₁₆) ÷ (¹/₆₄)" = "(¹/₁₆) * (⁶⁴/₁)" = (1*64) / (16*1) = 64/16 = "4" . Yes!
__________________________________________________________
When x = -2; the "output" is: "(¹/₆₄)" .
When x = -3; the "output" is: "(¹/₂₅₆)" ,
The ratio: "(¹/₆₄)/(¹/₂₅₆) = ? 4 " ? ;
→ "(¹/₆₄) / (¹/₂₅₆)" ;
= " (¹/₆₄) ÷ (¹/₂₅₆)" = " (¹/₆₄) * (²⁵⁶/₁) " = (1*256) / (64*1) = 256/164 = "4 " . Yes!
__________________________________________________________
→ So; as calculated; the ratio is: "4" ; which is:
__________________________________________________________
→ Answer choice: [B]: "4" .
__________________________________________________________