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Harrizon [31]
4 years ago
10

What is the output of the following code? var x = ["a", "b", "c"]; x.push("d", "e"); x.pop(); x.pop(); a. ​x = ["a", "b", "d", "

e"] b. ​x = ["d", "e"] c. ​x = ["a", "b", "c"] d. ​x = ["c", "d", "e"]
Computers and Technology
1 answer:
Fofino [41]4 years ago
3 0

Answer:

The answer to this question is option "C".

Explanation:

The stack is part of the data structure. In this stack perform two operations that are "push and pop". The push function is used to push(insert) and pop function is used to pop(delete) elements on the stack. It follows the LIFO process that stands for last in first out.

  • In this code, firstly we insert three elements on the stack that is "a, b and c".
  • Then, we insert two elements on the stack that is "d and e", in this element store in the upper part of the stack and then we call pop function two times.
  • In first time, the call will remove elements e and the second time it will remove element d.

That's why the answer is option "C".

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Write a program with total change amount as an integer input, and output the change using the fewest coins, one coin type per li
Contact [7]

Answer:

The program in python programming language is as follows

amount = int(input("Enter Amount:  "))

#Check if input is less than 1

if amount<=0:

     print("No Change")

else: #If otherwise

     #Convert amount to various coins

     dollar = int(amount/100) #Convert to dollar

     amount = amount % 100 #Get remainder after conversion

     quarter = int(amount/25) #Convert to quarters

     amount = amount % 25 #Get remainder after conversion

     dime = int(amount/10) #Convert to dimes

     amount = amount % 10 #Get remainder after conversion

     nickel = int(amount/5) #Convert to nickel

     penny = amount % 5 #Get remainder after conversion

     #Print results

     if dollar >= 1:

           if dollar == 1:

                 print(str(dollar)+" dollar")

           else:

                 print(str(dollar)+" dollars")

     if quarter >= 1:

           if quarter == 1:

                 print(str(quarter)+" quarter")

           else:

                 print(str(quarter)+" quarters")

     if dime >= 1:

           if dime == 1:

                 print(str(dime)+" dime")

           else:

                 print(str(dime)+" dimes")

     if nickel >= 1:

           if nickel == 1:

                 print(str(nickel)+" nickel")

           else:

                 print(str(nickel)+" nickels")

     if penny >= 1:

           if penny == 1:

                 print(str(penny)+" penny")

           else:

                 print(str(penny)+" pennies")

Explanation:

The program is written in python programming language and it uses comments to explain some lines

Variable amount is declared as integer

Line 3 checks if amount is less than or equal to 0

If yes, the program outputs No Change

Else, it converts the input amount to lesser coins

Line 7 of the program gets the dollar equivalent of the input amount

Line 8 gets the remainder

Line 9 gets the quarter equivalent of the remainder

Line 10 gets the remainder

Line 11 gets the dime equivalent of the remainder

Line 12 gets the remainder

Line 13 gets the nickel equivalent of the remainder

Line 14 gets the penny equivalent of the remainder

Line 16 till the end of the program prints the output and it uses appropriates name (singular and plural)

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Answer:

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  • <em>M.2 slot on the motherboard</em>
4 0
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