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Bumek [7]
2 years ago
15

What is the factor of this 3x - 12

Mathematics
1 answer:
MariettaO [177]2 years ago
4 0

Answer:

3 (x - 4)

Step-by-step explanation:

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(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
obtain the equation of two points passing of lines 4x-3y-1=0 and 2x-3y+3=0 and equally inclined to the axes​
klasskru [66]

Answer:By 8(4)P.5, the slope of the line equally inclined to axes is tan(±45  

o

)=±1. Hence by P+λQ=0,

5λ+3

2λ+4

​

=±1

⇒λ=  

3

1

​

,−1. Putting for λ, the two lines are

x−y=0,x+y−2=0.

Was this answer helpful

8 0
3 years ago
Kevin is 3 times as old as Daniel. 4 years ago, Kevin was 5 times as old as Daniel.
DochEvi [55]
X is Kevin; Y is Dan

X = 3Y

X - 4 = 5(Y - 4)


3Y - 4 = 5(Y - 4)   
3Y - 4 = 5Y - 20
     + 4         +4
4 cancels each other out.
     3Y = 5Y - 16
     - 5   -5
5 cancels each other out.
    -2Y = -16  
    /2       /2     
       Y = 8 

X = 3Y;    
X = 3 x 8;

Thus,
X = 24;
Kevin(x) is 24

8 0
4 years ago
This table models a linear function. x −8 −4 4 8 y −3 0 6 9 Enter the coordinates of the y-intercept in the boxes.
adell [148]

Answer:

y-intercept is 3

Step-by-step explanation:

We are given table

x: -8  -4  4  8

y: -3   0   6  9

We can select any two points

x_1=-8,y_1=-3

x_2=-4,y_2=0

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

now, we can plug values

m=\frac{0+3}{-4+8}

m=\frac{3}{4}\quad

now, we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y+3=\frac{3}{4}(x+8)

now, we can solve for y

y=\frac{3}{4}x+3

For finding y-intercept , we can plug x=0

y=\frac{3}{4}\times 0+3

y=0+3

y=3

So,

y-intercept is 3

8 0
3 years ago
What is the LCM of 3,5,7
Lubov Fominskaja [6]

Answer:

The least common multiple would be 105.

Step-by-step explanation:

You would do list out the multiples for each. Or multiply

Since 3 x 30 is 90, and 3 x 5  is 15, This is 105

And since 5 x 20 is 100, and 5 x 1 is 5, This is 105 as well

Also, since 7 x 10 is 70, and 7 x 5 is 35, This is 105.

The LCM is 105

Have a great Day!

4 0
4 years ago
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