Question

What is the product of 6 and 2 square root of 72 in simplest radical form?

Answer 1

Answer:

$72\sqrt{2}$

Step-by-step explanation:

$(6) 2\sqrt{72}$

Simplify the square root of 72 by finding perfect squares

$\sqrt{9(4)(2)}$

The square root of 9 = 3 and the square root of 4 = 2. Bring the 2 and 3 outside the square root.

$6(2)(2)(3)\sqrt{2}$

Multiply

6 x 2 x 2 x 3 = 72

$72\sqrt{2}$