(4 x 100) + (1 x 10) + (2 x 1) + (6 x 0.1) + (3 x 0.01) + (8 x 0.001)
Answer:
We conclude that:
- The number of people who ordered the chicken dinner = 1
- The number of people who ordered the steak dinner = 5
Step-by-step explanation:
Given that
- Some order the chicken dinner for $14
- some order the steak dinner for $17.
- Let 'n' be the number of people who ordered the chicken dinner.
- Let '6-n' be the number of people who ordered the steak dinner.
Thus, the equation becomes




Divide both sides by -3

and

Therefore, we conclude that:
- The number of people who ordered the chicken dinner = 1
- The number of people who ordered the steak dinner = 5
6 centimeters
x will represent the side length of the smaller square, so 2x is the side length of the bigger square.
x*x + 2x*2x = 45
x^2 + 4x^2 = 45
5x^2 = 45
x^2 = 9 (Divide by 5)
sqrt(x^2) = sqrt(9)
x = 3
2x = 6 (Multiply by 2)
Please consider marking this answer as Brainliest to help me advance.
Slope would be 2
Y intercept would be 2
y = 2x + 2
Answer:
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected individual will be between 185 and 190 pounds?
This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So
X = 190



has a pvalue of 0.8944
X = 185



has a pvalue of 0.7357
0.8944 - 0.7357 = 0.1587
15.87% probability that a randomly selected individual will be between 185 and 190 pounds