Ask question

Ask question

All categories

3 years ago

7

A Is a standard amount like a kilometer or gallon when used to communicate different quantities

1 answer:

Tatiana [17]3 years ago

6 0

I think the missing word you're looking for here is 'unit'. The examples such as kilogram and gallons are all units of measurement. These are standard amounts used for mass, volume, and length. It is especially important to be consistent with this units especially when doing dimensional analysis.

You might be interested in

Marie is puzzled by her findings she has done several meticulous calculations and has gotten the numbers .37 rad, .89 rad and 1.

Irina-Kira [14]

Answer:

I think the answer is a

Explanation:

for it to be accurate has be to exactly 0.9 rad

it is not precise because the answer she is getting is different everytime and not even close. For instance,

It would have been precise if she had gotten 0.37 rad in every attempt. or 0.89 every attempt...

6 0

3 years ago

75 kilometers per hour is an example of:<br> A. speed.<br> B. velocity<br> C. acceleration

kherson [118]

The answer is A. speed
hope this helps! :D

5 0

3 years ago

Read 2 more answers

The acceleration due to gravity at the surface of a planet depends on the planet's mass and size; therefore other planets will h

Cloud [144]

Chaff has also written about his book of Mormon that is not true to say this but it doesn't have the

5 0

3 years ago

A 1 530-kg automobile has a wheel base (the distance between the axles) of 2.70 m. The automobile's center of mass is on the cen

NeTakaya

Answer:

Force on front axle = 6392.85 N

Force on rear axle = 8616.45 N

Explanation:

As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels

Now we know that

$F_1 + F_2 = W$

$F_1 + F_2 = (1530\times 9.81)$

$F_1 + F_2 = 15009.3 N$

now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle

so we can write torque balance about its center of mass

$F_1(1.15) = F_2(2.70 - 1.15)$

$F_1 = 1.35 F_2$

now from above equation

$F_2 + 1.35F_2 = 15009.3$

now we have

$F_2 = 6392.85 N$

now the other force is given as

$F_1 = 8616.45 N$

4 0

3 years ago

As light from a star spreads out and weakens, do gaps form between the photons?

Sati [7]

Answer:

There are no gaps in space between the photons as they travel.

Yes, you can form the shadow of a fire

Explanation:

8 0

2 years ago

Read 2 more answers