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TiliK225 [7]
3 years ago
9

Please answer my last question got ignored

Mathematics
2 answers:
4vir4ik [10]3 years ago
7 0

Answer:

A. 136 sq. cm.

Step-by-step explanation:

First find the area of the rectangle:

16 times 7 is 112

13-7 is 6

16-8 is 8

The formula for the area of a triangle is ab/2

thus:

6 times 8 is 48/2

Which is 24

Add 112 with 24

Which is 136

Thus the answer is A. 136 sq. cm.

Hope this helps!

olchik [2.2K]3 years ago
7 0
The answer to your question is going to be The fist one A
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Extra points . Middle school work
4vir4ik [10]

Answer:

AcK!

Step-by-step explanation: It appears that the picture is upside down!! Id be glad to help if you take a new picture!

   -brainly expert

6 0
2 years ago
Please help me with this
a_sh-v [17]

Answer:

see explanation

Step-by-step explanation:

The geometric mean of 2 numbers a and b is \sqrt{ab}

The third term is the geometric mean of the first and fifth terms, that is

a₃ = \sqrt{3.5(283.5)} = 31.5

The second term is the geometric mean of the first and third terms, that is

a₂ = \sqrt{3.5(31.5)} = 10.5

The fourth term is the geometric mean of the third and fifth terms, that is

a₄ = \sqrt{31.5(283.5)} = 94.5

Thus the sequence is

3.5, 10.5, 31.5, 94.5, 283.5

6 0
4 years ago
I need to know what is 5÷ <br> 1<br> --<br> 4
Tresset [83]

the answer is 20, because in order to divide fractions you have to flip 1/4 to 4/1 then you multiply straight across, thus the answer is 20

3 0
3 years ago
The difference between a number and 12 is 20
Olenka [21]
X-12=20

Isolate x by adding 12 to both sides
x-12+12=20+12
x=32

Final answer: The number is 32.
Remember that difference is a keyword for subtraction.
8 0
3 years ago
Calculate x for each of the following right angled triangles.
Sphinxa [80]

\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} →}

<h3>(a) x = 6.5 cm </h3><h3>(b) x = 10 cm</h3><h3>(c) x = 7 cm</h3><h3>(d) x = 7.9 cm</h3>

Step-by-step explanation:

To find an unknown side of a right angled triangle we use a theorum called pythagorus theorum..

<h3>Formula :</h3>

(Hypotenuse)^2 = (Perpendicular)^2 + (Base)^2

(h)^2 = (p)^2 + (b)^2

<h3>therefore, </h3>

(a) hypotenuse = x cm, base = √30 cm, perpendicular = √12 cm.

<h3>by formula,</h3>

→ h^2 = p^2 + b^2

→ (x)^2 = (√12)^2 + (√30)^2

→ x^2 = 12 + 30

→ x^2 = 42

→ x = √42

→ x = 6.480...

→ x = 6.5 cm. (approx)

<h3>___________________________</h3>

(b) hypotenuse = √300 cm, base = √200 cm,perpendicular = x cm.

<h3>by formula,</h3>

→ h^2 = p^2 + b^2

→ (√300)^2 = (x)^2 + (√200)^2

→ 300 = x^2 + 200

→ x^2 = 300 – 200

→ x^2 = 100

→ x = √100

→ x= 10 cm.

<h3>___________________________</h3>

(c) hypotenuse = √66 cm, base = √17 cm,perpendicular = x cm.

<h3>by formula,</h3>

→ h^2 = p^2 + b^2

→ (√66)^2 = (x)^2 + (√17)^2

→ 66 = x^2 + 17

→ x^2 = 66 – 17

→ x^2 = 49

→ x = √49

→ x = 7 cm.

<h3>___________________________</h3>

(d) hypotenuse = x cm, base = 5√12 cm,perpendicular = 2√3 cm.

<h3>by formula,</h3>

→ h^2 = p^2 + b^2

→ (x)^2 = (2√3)^2 + (5√12)^2

→ x^2 = 12 + 50

→ x^2 = 62

→ x = √62

→ x = 7.874...

→ x = 7.9 cm. (approx)

<h3>___________________________</h3>

<h3>Hope it helps you!!</h3>
7 0
2 years ago
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