Answer:
(2,-17) should be the minimum.
Step-by-step explanation:
The minimum of a quadratic function occurs at 
. If a is positive, the minimum value of the function is 
occurs at
Find the value of
x = 2
evaluate f(2).
replace the variable x with 2 in the expression.
simplify the result.
The final answer is -17
Use the x and y values to find where the minimum occurs.
HOPE THIS HELPS!
<em>Greetings from Brasil...</em>
First degree equation. The variables are in the 1st member and the numbers in the 2nd member.
X + 6 - 2X = X - 24
X - 2X - X = - 24 - 6
- 2X = - 30
<h2>X = 15</h2>
F(x) = 2x + 5
-----------------------------------
Find f(x + 1) :
-----------------------------------
f(x +1) = 2(x + 1) + 5
f(x +1) = 2x + 2 + 5
f(x + 1) = 2x + 5
-----------------------------------
Find -2f(x+1):
-----------------------------------
-2(fx+1) = -2(2x + 5)
-2(fx+1) = -4x - 10
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Answer: -2(fx+1) = -4x - 10
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<h2>3</h2>
S<--->T
T<--->S
Same thing
<h2>4</h2>
Both sides a equivalent therefore both triangle areas are also equivalent
