Answer:
Step 1. Should be 3(x +2x) -2(x +1) +5 . . .
or . . . 3x(1 +2) -2(x +1) +5 . . .
or . . . 9x -2(x+1) +5
Step-by-step explanation:
Lisa apparently failed to realize that both terms inside the first set of parentheses have 3x as a factor. They are like terms, so could be combined directly. If Lisa really wants to factor out 3 or 3x, she could do so and then combine the remaining factors at another step.
You set it up as a y=mx+b problem 150=55x+40 then you subtract 40 from 150 making 110=55x so x=2
Given:
A fourth-degree polynomial function has zeros 4, -4, 4i , and -4i .
To find:
The fourth-degree polynomial function in factored form.
Solution:
The factor for of nth degree polynomial is:

Where,
are n zeros of the polynomial.
It is given that a fourth-degree polynomial function has zeros 4, -4, 4i , and -4i. So, the factor form of given polynomial is:


![[\because a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)
On further simplification, we get

![[\because i^2=-1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20i%5E2%3D-1%5D)
Therefore, the required fourth degree polynomial is
.