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Firlakuza [10]
3 years ago
13

Please HELP!!!

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0

Answer:

- 3, 1, 5, 9

Step-by-step explanation:

The first 4 terms are the values of y corresponding to x = 1, 2, 3, 4 , that is

(1, - 3 ) , (2, 1 ) , (3, 5 ) , (4, 9 )

first 4 terms are - 3, 1, 5, 9

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What are the alternate angle pairs in the picture below ?
polet [3.4K]

Given:

is the transversal that intersects the lines r and s.

Required:

Pairs of alternate exterior angles.

Explanation:

Line q intersects the lines r and s.

The alternate exterior angles are,

\angle2\text{ and }\angle8\text{ , }\angle1\text{ and }\angle7

Answer:

Thus the required answer is option 2.

5 0
1 year ago
Solve for the quotient 1 divided by 7
faltersainse [42]
I believe it's 1.4 you have to subtract 7 and 2 then divide what you get by 1
7 0
3 years ago
Look at the graphs and their equations below. Then fill in the information about the leading coefficients A overline B Cand D
Tresset [83]

Explanation

,the leading term is the term containing the highest power of x. The coefficient of the leading term is called the leading coefficient.

\begin{gathered} ax^2+bx+c=0 \\ a\text{ is the leading coefficient} \end{gathered}

Step 1

a)

an easy way to tell whether the graph of a quadratic function opens upward or downward: if the leading coefficient is greater than zero, the parabola opens upward, and if the leading coefficient is less than zero, the parabola opens downward.

therefore

\begin{gathered} graph\text{ A}\Rightarrow open\text{ downward}\Rightarrow negative \\ graphB\operatorname{\Rightarrow}open\text{upwards}\operatorname{\Rightarrow}pos\imaginaryI t\imaginaryI ve \\ graphC\operatorname{\Rightarrow}\text{ open upwards}\Rightarrow positive \\ graphD\operatorname{\Rightarrow}open\text{downward}\operatorname{\Rightarrow}negat\imaginaryI ve \end{gathered}

Step 2

b)the leading coefficient "a" indicates how "fat" or how "skinny" the parabola will be.

for

\begin{gathered} \lvert{leading\text{ coefficent}}\rvert>1,\text{ the parabola will be ''skinny''} \\ \lvert{\text{leadin coefficien}}\rvert

hence, more the skinny the graph is, the more closet to zero

therefore,the coefficient closest to 0 is C

Step 3

c)simiary, the graph with the leading coefficient with the grates value will be

graph B

because the coefficient is greater than zero and this graph is the more "fat"

I hope this helps you

4 0
1 year ago
I NEED HELP PLEASE!!!
netineya [11]

Answer:

F

Step-by-step explanation:

<3

3 0
3 years ago
Solve for the variable r in this equation: s = 2πrh
Ne4ueva [31]
S = 2(pi)rh.....divide both sides by 2(pi)h

s / (2(pi)h = r
5 0
3 years ago
Read 2 more answers
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