Answer:
<h3>
Assuming A, B, and C are collinear and B is between A and C then x = -2
2</h3>
Step-by-step explanation:
Assuming A, B, and C are collinear and B is beetween A and C
AB + BC = AC
48 + 2x + 139 = x + 165
2x + 187 = x + 165
x = -22
Answer:
n = 9
Step-by-step explanation:
20 + 18 + ... + 6 + 4
---------------------------
a = 20 ; d = -2 ; n = ?
--------
4 = 20 + (n-1)(-2)
-16 = (n-1)(-2)
---------
n-1 = 8
n = 9
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S(9) = (9/2)(20+4)
S(9) = 4.5*24
S(9) = 108
Use the proportion formula:
5mm/32= Xmm/160
=22.22 mm
Z-score for 80% to pass = -0.842.

-60.624 = X - 426
X = 426 - 60.624
X = 365
Therefore the required passing score is 365.
Answer:
mean ≈ 25.45
Step-by-step explanation:
mean is calculated as
mean = 
We require the sum for both classes
class A
mean =
= 40 ( multiply both sides by 9 )
sum = 9 × 40 = 360
class B
mean =
= 20 ( multiply both sides by 24
sum = 24 × 20 = 480
Total sum for both classes = 360 + 480 = 840 , then mean for both classes is
mean =
≈ 25.45 ( to 2 dec. places )