All categories

3 years ago

Which of the following equations has no solution?

Mathematics

1 answer:

Ronch [10]3 years ago

8 0

Answer:

B and D

Step-by-step explanation:

Equations with the same x- term on both sides will have no solution

4x - 13 = 5(x + 4) = 5x + 20

4x ≠ 5x

This equation has a solution

5(3 + 2x) = 10x + 4

15 + 10x = 10x + 4

10x on both sides ⇒ no solution

2(3 - 5x) = 8(x + 1)

6 - 10x = 8x + 8

- 10x ≠ 8x

This equation has a solution

9x - 6 = 3(3x - 2) = 9x - 6

9x on both sides ⇒ no solution

You might be interested in

0.84, 0.8, 0.81, 0.639 smallest to biggest

xenn [34]

Answer:

0.639, 0.84,0.81, 0.8,

Step-by-step explanation:

8 0

3 years ago

If f(x)=2x^2+(1000/x), find the average rate of change of f(x) from x=a to x=a+h.

galina1969 [7]

Answer:

$\frac{\frac{1000}{x+h}-\frac{1000}{x}}{h}$ is your average rate of change,

Step-by-step explanation:

average rate of change is

$\frac{f(a+h)-f(a)}{a+h-a}$ , by slope formula

simplify this to get $\frac{f(a+h)-f(a)}{h}$ , which is the definition of the derivative as h goes to 0

$\lim_{h \to 0} \frac{f(a+h)-f(a)}{h}$

since you defined x=a, we can substitute a for x and vice versa to find our derivative.

$\lim_{h \to 0} \frac{(2x^2+\frac{1000}{x+h})-(2x^2+\frac{1000}{x})}{h}$

simplifying

$\lim_{h \to 0} \frac{\frac{1000}{x+h}-\frac{1000}{x}}{h}$ (your average rate of change)

6 0

3 years ago

To ride a roller coaster, a visitor must not be less than 58 inches tall.

sattari [20]

Answer:

h≥58

Step-by-step explanation:

h=visitor able to ride

you must be 58 inches to ride

Thus h is greater than or equal to 58

h≥58

4 0

3 years ago

Which pair of angles in the figure below are vertical angles? Check all that apply

Firdavs [7]

Answer:

Step-by-step explanation:

and

< SYL and <EYA

Step-by-step explanation:

Vertical angles can be defined as the pair of angle which are opposite when two lines crosses, as the image attached shows.

Now, <EYL and <AYS are vertical angles, because they are opposite when lines ES and AL cross at point Y.

Another pair of vertical angles are <SYL and <EYA, because they are opposite when lines ES and AL cross at point Y.

Therefore, all pair of angles which are vertical angles are

<EYL and <AYS

< SYL and <EYA

REMENBER : VERTICAL LINEA

8 0

3 years ago

How to determine whether the pair of lines is parallel perpendicular or neither?

kodGreya [7K]

If the slopes of the 2 lines are equal then they are parallel.

If m1m2 = -1 (where m1 and m2 are the slopes of the 2 lines) then they are perpendicular.

If the 2 slopes do not match either the first or second conditions then they are neither parallel or perpendicular.

6 0

3 years ago