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Answer:
The height of ball is 17 ft at t=0.55 and t=1.14.
Step-by-step explanation:
The general projectile motion is defined as
Where, v is initial velocity and y₀ is initial height.
It is given that the initial height is 7 and the initial upward velocity is 27.
Substitute v=27 and y₀=7 in the above equation to find the model for height of the ball.
The height of ball is 17 ft. Put h(t)=17.
On solving this equation using graphing calculator we get
Therefore the height of ball is 17 ft at t=0.55 and t=1.14.