-np-4≤2(c-3)
-np-4≤2x-6
-np≤2x-2
-n≤(2x-2)/p
n≥-((2x-2)/p)
Answer: You take the last two digits of the original number and see if they are divisible by 4.
Step-by-step explanation: Take your original number and find the last two digits. If they are divisible by 4, then the original number is divisible by 4.
Answer:
take a screen shot and then post it
Step-by-step explanation:
mark me brainlist
Cross multiplying we get
x^2 = 2*7x
x^2 = 14x
x^2 - 14x = 0 is the answer
I just graphed all 4 and didn’t see where any are on the same horizontal line. I might be missing something.
