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kap26 [50]
3 years ago
6

A 0.5 kg ball is tied to a swung in a circle with a radius of 0.400m.If the ball is accelerating at 58.8 m/s^2,what is the tange

ntial velocity of the ball?
Physics
1 answer:
jeka57 [31]3 years ago
5 0
If the acceleration is centripetal then the formula is a=v^2/r
Plug in 58.8=v^2/.400 solve for v
V=12.12 m/s
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Is there a unit of measure called potential
Umnica [9.8K]
No. Potentional (other wordy here) are a few of though.
4 0
3 years ago
In which position does the ball have the least potential energy but the most kinetic energy
Firdavs [7]

Answer:

position 2

Explanation:

the gravity from the ball to the floor had the most movement involved.

5 0
4 years ago
A charge of 2.00 μC flows onto the plates of a capacitor when it is connected to a 12.0-V potential source. What is the minimum
uysha [10]

To develop this problem we will apply the concept of energy conservation. For which the work carried out must be equivalent to the potential energy stored on the capacitor. We will start by finding the capacitance to later be able to calculate the energy and therefore the work in the capacitor

C = \frac{Q}{V}

Here,

C = Capacitance

V = Potential difference between the plates

Q = Charge between the capacitor plates

At the same time the energy stored in the capacitor can be defined as,

U = \frac{1}{2} CV^2

We will start by finding the value of the capacitance, so we will have to,

C = \frac{2\mu C}{12.0V}

C = 0.166\mu F

Finally using the expression for the energy we have that,

U = \frac{1}{2} CV^2

U = \frac{1}{2} (0.166\muF)(12.0V)^2

U = 11.0*10^{-6} J

Therefore the minimum amount of work that must be done in charging this capacitor is 11.0*10^{-6} J

8 0
3 years ago
Read 2 more answers
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oee [108]

Answer:

1. A

sound can't travel through vacuum only

6 0
3 years ago
Calculate the frequency (v) in Hertz (Hz) of a wave that has a wavelength of 4.71 meters.
MissTica

Answer:

6.37 x 10⁷Hz

Explanation:

Given parameters:

Wavelength = 4.71m

Unknown:

Frequency  = ?

Solution:

To solve this problem, we use the expression below:

           V = F∧  

V is the velocity  = 3 x 10⁸m/s

F is the frequency

∧ is the wavelength

  3 x 10⁸  = F x 4.71

      F  = 63694267.52Hz = 6.37 x 10⁷Hz

           

6 0
3 years ago
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