Answer:
<h2>
<em>=</em><em> </em><em>2</em><em>4</em><em>5</em><em>.</em><em>2</em><em>5</em></h2>
Explanation:
<h3>150 x 7.5 x 9.81 =11036.25</h3><h3>ans / 60 =183.9</h3><h3>ans / 75 x 100 = 245.25</h3>
Given:
refractive index: diamond = 2.42 ; air = 1
90° should have been provided in the problem. I encountered similar problem before.
Using Snell's Law: n1*sin(a) = n2*sin(b)
where:
n1 and n2 are the refractive indexes
sin(a) and sin(b) are the corresponding angles.
n1 = 2.42
n2 = 1.00
b = 90°
n1 * sin(a) = n2 * sin(b)
2.42 * sin(a) = 1 * 1
2.42 * sin(a) = 1
sin(a) = 1 / 2.42
sin(a) = 24.4° Choice B.
Answer:
Option 2 is the correct answer.
Explanation:
I f the work done by a force does not depend upon the path of mass then the force is called conservative force.
Work done by frictional force depends upon path followed by mass, so frictional force is a non conservative force. But work done by gravitational force does not depend upon path followed by mass, so gravitational force is a conservative force.
Option 2 is the correct answer.
Vox = ?
Voy = 0 m/s
g = 9.8 m/s
s = 61.7 m
h = 42.4 m
(1)-----------------------------------...
To find the time taken for the ball to travel to the bottom:
For constant acceleration,
s = Voy*t + 0.5*g*t^2
42.4 = 0 + 0.5(9.8)*t^2
t^2 = 42.4 / 4.9
t^2 = 8.6531
t = 2.9417s
(2)-----------------------------------...
For the intial velocity of the horizontal component (Vox) of the ball:
s = Vox*t + 0.5*a*t^2
There is no force acting on the horizontal component, so there is no acceleration.
s = Vox*t
61.7 = 2.9417*Vox
Vox = 181.5029 m/s
(3)-----------------------------------...
Since there is no acceleration acting on the horizontal component, x, it remains constant throughout.
Hence, it is still 181.5029 m/s.
For the final velocity of the vertical component (Vfy) of the ball:
(Vfy)^2 = (Voy)^2 + 2*a*h
Acceleration in this case is the force of gravity.
(Vfy)^2 = 0 + 2*(9.8)*(42.4)
(Vfy)^2 = 831.04
Vfy = 28.8278 m/s
I've clearly explained every step. Hope that answers your question! =D
Diffuse reflection occurs <span>when parallel light waves strike a rough, uneven surface</span>.
