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3 years ago

Can someone explain and slove question 4

Physics

1 answer:

Sonbull [250]3 years ago

6 0

A. NaOH
B. PbNO3
C. FeSO4
D. P2O3
E. CSe2
F. HC2H3O2
G. HCIO
H. H2SO4

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Question 9 of 34

Rufina [12.5K]

Answer:

Option B) Displacement

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2 years ago

During a certain nuclear reaction the total mass of the products is less than the total mass of reactants what happened to the m

miss Akunina [59]

Answer: it turns into energy

Explanation: In a nuclear fusion reaction, two reactants combine, and form new products. But the mass of the products is less than total mass of the reactants. This is because a part of mass is lost as energy. This can be seen in an example shown below. You can see that mass is of the products is less than that of the reactants.

Hope This Helps :)

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2 years ago

Suppose that a particular artillery piece has a range R = 9880 yards . Find its range in miles. Use the facts that 1mile=5280ft

Solnce55 [7]

Answer:

R = 9880 yd * 3 ft/yd / 5280 ft/mi = 5.61 mi

If you do it in steps

R = 9880 yd * 3 ft/yd = 29640 ft

R = 29640 ft / 5280 ft/mi = 5.61 mi

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3 years ago

A 4.00 µf capacitor is connected to a 12.0 v battery.

atroni [7]

(a) The capacitance of the capacitor is:
$C=4 \mu F=4 \cdot 10^{-6}F$
and the voltage applied across its plates is
$V=12.0 V$

The relationship between the charge Q on each plate of the capacitor, the capacitance and the voltage is:
$C= \frac{Q}{V}$
and re-arranging it we find the charge stored in the capacitor:
$Q=CV=(4 \cdot 10^{-6} F)(12.0 V)=4.8 \cdot 10^{-5} C$

(b) The electrical potential energy stored in a capacitor is given by
$U= \frac{1}{2}CV^2$
where C is the capacitance and V is the voltage. The new voltage is
$V=1.50 V$
so the energy stored in the capacitor is
$U= \frac{1}{2}(4 \cdot 10^{-6} F)(1.50 V)^2=4.5 \cdot 10^{-6} J$

3 0

3 years ago

Read 2 more answers

A cylinder of gas at room temperature has a pressure . To p_{1} what temperature in degrees Celsius would the temperature have t

grandymaker [24]

In order to calculate the temperature, we need to know that temperature and pressure are directly proportional, that is, if the pressure increases, the temperature (in Kelvin) also increases in the same proportion.

So, first let's convert the temperature from Celsius to Kelvin, by adding 273 units:

$\begin{gathered} K=C+273 \\ K=20+273 \\ K=293 \end{gathered}$

Then, let's calculate the proportion:

$\begin{gathered} \frac{P_1}{T_1}=\frac{P_2}{T_2} \\ \frac{p_1}{293}=\frac{1.5p_1}{T_2} \\ \frac{1}{293}=\frac{1.5}{T_2} \\ T_2=1.5\cdot293 \\ T_2=439.5\text{ K} \end{gathered}$

Now, converting back to Celsius, we have:

$\begin{gathered} C=K-273 \\ C=439.5-273 \\ C=166.5\text{ \degree{}C} \end{gathered}$

So the temperature would be 166.5 °C.

6 0

1 year ago