Solve this using Olm's law, which relates current (C), voltage (V), and resistance (R). Olm's law says:
We are told that voltage, V = 12V, and resistance, R = 4.8 <span>Ω. Plug these values into the equation and solve for current:
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Answer: Current = 2.5 Amperes</span>
Answer:
5N
Explanation:
Given parameters:
Original length = 22cm
Spring constant, K = 50N/m
New length = 32cm
Unknown
Force applied = ?
Solution:
The force applied on a spring can be derived using the expression below;
Force = KE
k is the spring constant
E is the extension
extension = new length - original length
extension = 32cm - 22cm = 10cm
convert the extension from cm to m;
100cm = 1m;
10cm will give 0.1m
So;
Force = 50N/m x 0.1m = 5N
Answer:
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Explanation:
Given initial velocity of ambulance
v0=18m/s , acceleration a=5m/s2
To find distance, x=?
First we need to calculate the time for which it acquires 30\,m/s. For that use equation
v=v0+at
30=18+5×t
⇒t=30−185=125seconds
Distance travelled by the ambulance
x=v0t+12at2
x=(18×125)+12×5×(125)2
x=43.2+2.5×5.76=43.2+14.4
x=57.6m
Therefore the ambulance has to travel 57.6 m to match the velocity of car.
Answer:
Explanation:
Sample Response: Yes, the law of conservation of momentum is satisfied. The total momentum before the collision is 1.5 kg • m/s and the total momentum after the collision is 1.5 kg • m/s. The momentum before and after the collision is the same.
