Answer:
90 m/s
8100 m
Explanation:
Given:
v₀ = 0 m/s
a = 0.5 m/s²
t = 3 min = 180 s
Find: v and Δx
v = at + v₀
v = (0.5 m/s²) (180 s) + 0 m/s
v = 90 m/s
Δx = v₀ t + ½ at²
Δx = (0 m/s) (180 s) + ½ (0.5 m/s²) (180 s)²
Δx = 8100 m
Acceleration of block = net force/mass = 10/2 = 5 m/s²
A frame of reference can be thought of as the state of motion of the observer of some event. For example, if you're sitting on a lawn chair watching a train travel past you ... you could even watch a glass of water sitting on a table inside the train move ... This seems like a simple and obvious example, yet when you take a step
1) PE=mgh
mass 50 kg; height 3; g 9.81
50×3×9.81=1471.5 J
2. The student is opposing gravity force so
Fgrav=m×g
50 × 9.81= 490N
Work=force×displacement
490×3=1470J(this should always be the same as the potential energy)
3.Power=work×time
4410 W=1470×3
4. Greater than: power is dependent on work, work is dependent on force, force is dependent on weight,
