Ask question

Ask question

All categories

3 years ago

9

Solve the inequality: 4x-2>10 or 7+3x<2x+6

1 answer:

Galina-37 [17]3 years ago

6 0

Answer:

SteP-by-step explanation:

4x−2=10

1 Let x=3x=3.

4\times 3-2=10

4×3−2=10

2 Simplify 4\times 34×3 to 1212.

12-2=10

12−2=10

3 Simplify 12-212−2 to 1010.

1 0 =10

10=10

--

You might be interested in

X+4/x-1 divided by x^2 +x/x-1<br> 3/2x-1 subtract by 5/2x-1 <br> how do you do them

ElenaW [278]

$\frac{x + 4}{x - 1} / \frac{x^{2} + x}{x - 1} = \frac{x + 4}{x - 1} * \frac{x^{2} + x}{x - 1} = \frac{(x + 4)(x^{2} + x)}{(x - 1)(x - 1)} = \frac{x^{3} + x^{2} + 4x^{2} + 4x}{x^{2} - x - x + 1} = \frac{x^{3} + 5x^{2} + 4x}{x^{2} - 2x + 1} = x + 7 + \frac{17x - 7}{x^{2} - 2x + 1}$

$\frac{3}{2x - 1} - \frac{5}{2x - 1} = -\frac{2}{2x - 1}$

6 0

3 years ago

Fill in the puzzle square to make the same sum from whatever direction you add for grade 4

lidiya [134]

Answer:

box e goes:

17, 10, 15

12, 14, 16

13, 18, 11

6 0

3 years ago

Use the annual compound interest formula to find the amount in the savings account at the end of the time period and then find t

icang [17]

Answer:

$9,216 in account $1,261 interest.

Step-by-step explanation:

The compound interest is given by:

$a = p(1 + \frac{r}{n})^{nt}$

P = Principal

r = rate

n = Number of times interest is compounded per unit t

t = time

so:

$a = 8000(1 + \frac{0.05}{1} ) ^{1 .3} \\ a = 9261$

therefore, the answer is:

$9,216 in account $1,261 interest

8 0

3 years ago

Keisha is walking around a track that is 400 yards long. How many more yards does she need to walk around the track to complete

lutik1710 [3]

400x4 is 1 mile so 400x8 is 2 miles so 3,200 is 2 miles minus 400 because she already walked that so the answer is 2,800

6 0

3 years ago

What must be the sides of an equilateral triangle so that it's area should be equal to the area of an isosceles triangle with ba

d1i1m1o1n [39]

Answer:

The sides of the equilateral triangle are 11.7 m.

Step-by-step explanation:

Let's find the area of the isosceles triangle:

$A_{i} = \frac{bh}{2}$

Where:

b: is the base = 12 m

h: is the height

We can find the height by using Pitagoras:

$x^{2} = \frac{b^{2}}{2} + h^{2}$

Where:

x is the hypotenuse = side of the triangle = 10 m

$h = \sqrt{x^{2} - \frac{b^{2}}{2}} = \sqrt{(10)^{2} - 6^{2}} = 8 m$

Then, the area is:

$A_{i} = \frac{12*8}{2} = 48 m^{2}$

Now, since the area of the isosceles triangle is equal to the area of the equilateral triangle:

$A_{e} = A_{i} = 48 m^{2}$

$A_{e} = \frac{bh}{2}$

The height of the equilateral triangle is given by:

$b^{2} = \frac{b^{2}}{2} + h^{2}$

$h = \sqrt{b^{2} - \frac{b^{2}}{2}} = \frac{b}{\sqrt{2}}$

Hence, the sides are:

$A_{e} = \frac{1}{2}b\frac{b}{\sqrt{2}} = \frac{b^{2}}{2\sqrt{2}}$

$b = \sqrt{A*2\sqrt{2}} = \sqrt{48*2\sqrt{2}} = 11.7 m$

Therefore, the sides of the equilateral triangle are 11.7 m.

I hope it helps you!

7 0

3 years ago

Read 2 more answers