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netineya [11]
3 years ago
13

Evaluate 24-(7-2+x) when x=4(show work) ​

Mathematics
2 answers:
sergejj [24]3 years ago
8 0

\large\text{Hey there!}

\large\boxed{\mathsf{24 - (7 - 2 + 4)}}\\\\\large\boxed{\mathsf{= 24 - (5 + 4)}}\\\\\large\boxed{\mathsf{= 24 - 9}}\\\\\large\boxed{\mathsf{= 15}}\\\\\large\text{Therefore, your answer is: \huge\boxed{\mathsf{15}}}\huge\checkmark

\large\text{Good luck on your assugnment \& enjoy your day!}\\\\\frak{Amphitritr1040:)}

solmaris [256]3 years ago
4 0

Answer:19

Step-by-step explanation:

Subtract 2 from 7 to get 5

To find the opposite of 5+x, find the opposite of each term.

Subtract 5 from 24 to get 19.

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Write an equation of a line that passes through (3, -1) and is parallel and perpendicular to y = 6x - 4
Serhud [2]

Here,

y=mx+c

the slope of the line 6x+4y= -16 is -20.

if the two lines are perpendicular, the slope of 1st line * slope of second line=-1

the slope of the 2nd line is -1/2

y-y1=m(x-x1)

y-13=-1/2(x- -18)

when you solve, you get the equation of the line as 2y+x=50

In basic geometry, if two geometry objects intersect at right angles (90 degrees or π / 2 radians), they are vertical.

If two lines intersect at right angles, the line is perpendicular to another line. Explicitly (1) if two lines intersect, the first line is perpendicular to the second line. (2) At the intersection, the straight line angle on one side of the first line is cut by the second line into two congruent angles. Verticality can be shown as symmetric. That is, if the first line is perpendicular to the second line, then the second line is also perpendicular to the first line. Therefore, two straight lines can be said to be perpendicular (to each other) without specifying the order.

Learn more about Perpendicular here: brainly.com/question/7098341

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4 0
2 years ago
Which is the angle of depression from b to c
matrenka [14]

<2

Step-by-step explanation:

that the answer. because it below par

8 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
the ratio of reds to greens was 5 to 16 and six times the number of reds exceeded the number of greens by 112. how many were red
Masja [62]
Call red as X then X/Green =5/16 => green = 16X/5.
six times the number of reds exceeded the number of green by 112 => 6X-16X/5=112 => 14X/5=112 => X= 40 => reds:40 => green = 128
7 0
4 years ago
Simplify the expression z^2-z(z+3)+3z
Alisiya [41]
<span>z^2-z(z+3)+3z

z^2 - z^2 - 3z + 3z

0 + 0

0

</span><span>z^2-z(z+3)+3z = 0</span>
5 0
3 years ago
Read 2 more answers
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