Ask question

Ask question

All categories

3 years ago

7

A charged particle is located in an electric field where the magnitude of the electric field strength is 2.0x10^3 newtons per co

ulomb. If the magnitude of the electrostatic force exerted on the particle is 3.0x10^-3 newton, what is the charge of the particle?

1 answer:

Alexxandr [17]3 years ago

6 0

Answer:

20.7

Explanation:

:0 because basis of the daily occured

You might be interested in

Write the energy conversion when climbing a ladder

Volgvan

A child climbing a ladder is transforming kinetic energy into potential energy.

7 0

3 years ago

If the distance of a galaxy is 2,000 Mpc, how many years back into the past are we looking when we observe this galaxy

ruslelena [56]

The age of the galaxy when we look back is 13.97 billion years.

The given parameters:

<em>distance of the galaxy, x = 2,000 Mpc</em>

According Hubble's law the age of the universe is calculated as follows;

v = H₀x

where;

H₀ = 70 km/s/Mpc

$T = \frac{x}{V} \\\\T = \frac{x}{xH_0} \\\\T = \frac{1}{H_0} \\\\T = \frac{1}{70 \ km/s/Mpc} \\\\T = \frac{1 \ sec}{70 \times 3.24 \times 10^{-20} } \\\\T = 4.41 \times 10^{17} \ sec\\\\T = \frac{4.41 \times 10^{17} \ sec\ \times \ years}{3600 \ s \ \times\ 24\ h\ \times \ 365.25 \ days} \\\\T = 1.397 \times 10^{10} \ years\\\\T = 13.97 \ billion \ years$

Thus, the age of the galaxy when we look back is 13.97 billion years.

Learn more about Hubble's law here: brainly.com/question/19819028

8 0

3 years ago

Where are the nodules of a legume found?

Sveta_85 [38]

Answer:

The answer is roots.

Explanation:

Root nodules are found on the <em>roots of plants</em>, primarily legumes, that form a symbiosis with nitrogen-fixing bacteria. so it is roots

6 0

4 years ago

A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, p=75 psip=75 psi. It had a wall thickness

Mekhanik [1.2K]

To solve this problem we must apply the concept related to the longitudinal effort and the effort of the hoop. The effort of the hoop is given as

$\sigma_h = \frac{Pd}{2t}$

Here,

P = Pressure

d = Diameter

t = Thickness

At the same time the longitudinal stress is given as,

$\sigma_l = \frac{Pd}{4t}$

The letters have the same meaning as before.

Then he hoop stress would be,

$\sigma_h = \frac{Pd}{2t}$

$\sigma_h = \frac{75 \times 8}{2\times 0.25}$

$\sigma_h = 1200psi$

And the longitudinal stress would be

$\sigma_l = \frac{Pd}{4t}$

$\sigma_l = \frac{75\times 8}{4\times 0.25}$

$\sigma_l = 600Psi$

The Mohr's circle is attached in a image to find the maximum shear stress, which is given as

$\tau_{max} = \frac{\sigma_h}{2}$

$\tau_{max} = \frac{1200}{2}$

$\tau_{max} = 600Psi$

Therefore the maximum shear stress in the pressure vessel when it is subjected to this pressure is 600Psi

6 0

3 years ago

Why does paper attract both positive and negative charges? Explain.

Sedbober [7]

The fibers have lost electrons giving them a positive charge. The rubber gained electrons giving it a negative charge. The positively charged fibers are now attracted to the negatively charged balloon. The negatively charged balloon attracts the paper.

5 0

2 years ago