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Kisachek [45]
3 years ago
10

HELP ASAP! GIVING BRAINLIEST

Physics
2 answers:
Sergio [31]3 years ago
8 0

Answer:

Sound energy..

Explanation:

alina1380 [7]3 years ago
5 0

Answer: Kinetic Energy?

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Select the volume units that are greater than one liter.
Andreas93 [3]
A.) kiloliter. 1 kiloliter = 1,000 liters
c.) megaliter. 1 megaliter =  1,000,000 liters


hope this helps
5 0
3 years ago
Read 2 more answers
Help?? ....... ┐(‘~`;)┌​
7nadin3 [17]

Answer:

(3) Both extensional as well as compressional strain is produced

Explanation:

8 0
2 years ago
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Students measured the mass of 25.0 mL of water and found it be 25.4 g. The accepted mass is 25.0 g. What is the percent error of
Andre45 [30]
Well first of all, I think the students may have been correct. 
If they didn't use distilled water, and if it wasn't exactly at 
standard temperature, then the mass of  25.0 mL  could
very well be  25.4 grams.  We don't know that there was
any 'error' in their measurement at all.
But the question says there was, so we'll do the math:

The 'error' was  (25.4 - 25.0) = +0.4 gram

As a fraction of the 'real' value, the error was

                            +0.4 / 25.0  =  +0.016 .

To change a decimal to a percent, move the
decimal point two places that way  ===> .

                           + 0.016  =  +1.6 % .

     
Their measurement was 1.6% too high.

Let's not call it an 'error'.  Let's just call it a 'discrepancy'
between the measured value and the 'accepted' value.  OK ?
4 0
3 years ago
Read 2 more answers
Is the acceleration change or constnt?​
marin [14]
Change.

Acceleration means going faster
4 0
2 years ago
How much heat is needed to warm 0.072kg of gold from 20 celsius and 90 celsius if the specific heat of gold 136 joules
dybincka [34]

Heat supplied to the gold will raise the temperature of the gold from 20 degree Celsius to 90 degree Celsius.

Mass of the gold (m) = 0.072 kg

Temperature change (ΔT) = 90 - 20 = 70 degree Celsius

Specific heat capacity of the gold (c) = 136 J/kg C

Heat supplied = m × c × ΔT

Heat supplied = 0.072 × 136 × 70

Heat supplied = 685.44 Joules

Hence, the heat supplied to the gold to raise the temperature from 20 degree Celsius to 90 degree Celsius = 685.44 Joules

5 0
3 years ago
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