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Lynna [10]
3 years ago
11

Jerry has a lot of cousins! He has 5 times as many younger cousins as older cousins. If Jerry has 12 more younger cousins than o

lder cousins, how many cousins does he have altogether?
Mathematics
1 answer:
castortr0y [4]3 years ago
7 0

Answer: 3

Step-by-step explanation:

5*x=12+x

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Hiro painted his room at a rate of 8 square meters per hour. After 3 hours of painting, he had 28 square meters left to paint. L
lesya692 [45]

Answer: A(t)=-8t+52

Step-by-step explanation:

<h3> The missing question is: "What is the Functions formula A(t)=?"</h3><h2 />

The  equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

According to the data given in the exercise, you know that:

- A(t) represents the area to paint the Hiros' romm as a function of time.

- The rate he painted the room was 8 square meters per hour.

- The area left to paint after 3 hours was 28 m².

Therefore, based on this, you can idenfity that:

1. The slope of the line is:

m=-8

2. One of the point on the line is:

(3,28)

So you must substitute the slope and the coordinates of that point into y=mx+b and then solve for "b" in order to find its value:

28=-8(3)+b\\\\28+24=b\\\\b=52

Therefore, you can determine that the function A(t) is:

A(t)=-8t+52

4 0
3 years ago
What is the greatest factor of 63 that is also a prime number?<br> 7<br> 9<br> 13<br> 21
Brums [2.3K]

Answer:

7

Step-by-step explanation:

Note the factors of each number. Prime numbers are numbers that can only be factored to itself and 1. Note:

Factors of 1:

1

Factors of 3:

1 , 3

Factors of 7:

1 , 7

Factors of 9:

1 , 3 , 9

Factors of 21:

1 , 3 , 7 , 21

Factors of 63:

1 , 3 , 7 , 9 , 21 , 63

6 0
3 years ago
Read 2 more answers
Which graph represents the following piecewise defined function?
kenny6666 [7]
The correct answer is shown in attached figure
To find the correct graph, we should study the continuity of the function

Check the continuity at x = -2
from the left ⇒⇒ f(-2) = 1/2 * -2 + 3 = 2
from the right ⇒⇒ f(-2) = 2
∴ The function is continuous at x = -2

Check the continuity at x = 3
from the left ⇒⇒ f(3) = 2
from the right ⇒⇒ f(3) = 2*3 - 3 = 3
∴ The function is jump discontinuous at x = 3


From the previous results the correct graph is the last as shown in attached graph.



5 0
3 years ago
Read 2 more answers
The points (–2, 4) and (–2, –2) are vertices of a heptagon. Explain how to find the length of the segment formed by these endpoi
Scrat [10]

Answer:

The segment is 6 units long.

Step-by-step explanation:

The points (–2, 4) and (–2, –2) are vertices of a heptagon. We have to explain how to find the length of the segment formed by these endpoints.

If two points at the ends of a straight line PQ are P(x_{1},y_{1}) and Q(x_{2},y_{2}), then the length of the segment PQ will be given by the formula  

\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}

Now, in our case the two points are (-2,4) and (-2,-2) and the length of the segment will be  

\sqrt{(- 2 - (- 2))^{2} + (4 - (- 2))^{2}} = 6 units. (Answer)

5 0
4 years ago
Read 2 more answers
Which of the number(s) below are potential roots of the function? p(x) = x4 + 22x2 – 16x – 12
Neporo4naja [7]

Complete question is;

Which of the number(s) below are potential roots of the function? p(x) = x⁴ + 22x² – 16x – 12

A) ±6

B) ±1

C) ±3

D) ±8

Answer:

Options A, B & C: ±6, ±1, ±3

Step-by-step explanation:

We are given the polynomial;

p(x) = x⁴ + 22x² – 16x – 12

Now, the potential roots will be all the rational numbers equivalent of p/q.

Where;

p are the factors of the constant term of the polynomial

q are the factors of the leading coefficient of the polynomial

Now, in the given polynomial, the constant term is seen as -12 while leading coefficient is 1 which is the coefficient of x⁴.

We know that factors of 12 are any of:

±1, ±2, ±3, ±4, ±6 and ±12

While possible factors of 1 is just ±1.

Thus, all the potential roots of the polynomial function are;

±1, ±2, ±3, ±4, ±6 and ±12

From the options given, option A, B & C could be the potential roots.

6 0
3 years ago
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