Answer:
b. 10a³ - 11a - 3
Step-by-step explanation:
1. Expand 3(a³ - 2a - 5)
= 3a³ - 6a - 15
2. Add 7a³ - 5a + 12 and 3a³ - 6a - 15
7a³ + 3a³ = 10a³
-5a + -6a = -11a
12 + -15 = -3
3. Answer: b. 10a³ - 11a - 3
Answer:
Step-by-step explanation:
1
. Start by making a "let statement."
Let
x
represent the weight of the package.
2
. Create an algebraic expression.
5
7
x
=
40.5
i
pounds
3
. Isolate for
x
by dividing both sides by
5
7
.
5
7
x
÷
5
7
=
40.5
i
pounds
÷
5
7
4
. Recall that in order to divide a fraction by another fraction, take the reciprocal of the divisor and change the division sign to a multiplication sign.
5
7
x
⋅
7
5
=
40.5
i
pounds
⋅
7
5
5
. Solve for
x
.
5
⋅
7
7
⋅
5
x
=
40.5
⋅
7
5
i
pounds
x
=
∣
∣
∣
∣
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
a
a
56.7
i
pounds
a
a
∣
∣
−−−−−−−−−−−−−−−
Answer:0
Step-by-step explanation:
You could simplify this work by factoring "3" out of all four terms, as follows:
3(x^2 + 2x - 3) =3(0) = 0
Hold the 3 for later re-insertion. Focus on "completing the square" of x^2 + 2x - 3.
1. Take the coefficient (2) of x and halve it: 2 divided by 2 is 1
2. Square this result: 1^2 = 1
3. Add this result (1) to x^2 + 2x, holding the "-3" for later:
x^2 +2x
4 Subtract (1) from x^2 + 2x + 1: x^2 + 2x + 1 -3 -1 = 0,
or x^2 + 2x + 1 - 4 = 0
5. Simplify, remembering that x^2 + 2x + 1 is a perfect square:
(x+1)^2 - 4 = 0
We have "completed the square." We can stop here. or, we could solve for x: one way would be to factor the left side:
[(x+1)-2][(x+1)+2]=0 The solutions would then be:
x+1-2=0=> x-1=0, or x=1, and
x+1 +2 = 0 => x+3=0, or x=-3. (you were not asked to do this).
Well you would take 53% then put it over 100 so you should get 53/100
