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kherson [118]
3 years ago
13

How to a magic square decmals

Mathematics
1 answer:
Wewaii [24]3 years ago
4 0
You just count. relugar. like (exzample

1 2 and of it's a three here ➡3 change it to a one and count rulgar and put the decimal

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Judith puts $9,373.00 into an account to use for school expenses. The account eams 9% interest, compounded monthly. How much wil
vlabodo [156]

Answer:

After 7 years they would have $17,557.52

Step-by-step explanation:

7 0
2 years ago
Suppose Brianna invests $1,300 each year for 5 years, in an annuity that pays 6% annual interest, compounded annually. What perc
love history [14]

Answer:

74.73%

Step-by-step explanation:

First, we're gonna find out her total amount

We're gonna use the count interest formula: P = A(1 + r)ⁿ

P = final amount

A = starting amount (1300)

r = rate (0.06)

n = years (5)

P = 1300(1 + 0.06)⁵

P = 1739.693251

Now divide the starting amount by the total amount

1300 ÷ 1739.693251 = 0.7472582

7 0
3 years ago
In speed skating, the distance of 10,000 meters consists of 25 laps. A skater sets the
xxMikexx [17]

Answer:

B) -0.4 seconds

Step-by-step explanation:

Laps: 25

Goal: -10 seconds to all 25 laps combined (10 seconds difference => -10)

divide by total laps

-10 /25 = -0.4s difference each lap

6 0
3 years ago
A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it
natima [27]

Answer:

h = 61.25 m

Step-by-step explanation:

It is given that,

The initial velocity of the ball, v = 60 m/s

It is thrown from a height of 5 feet, h_o=5\ ft

We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

h=-16t^2+vt+h_0

Putting all the values,

h=-16t^2+60t+5 .....(1)

For maximum height, put

\dfrac{dh}{dt}=0\\\\\dfrac{-16t^2+60t+5}{dt}=0\\\\-32t+60=0\\\\t=\dfrac{-60}{-32}\\\\t=1.875\ s

Put t = 1.875 in equation (1)

h=-16(1.875)^2+60(1.875)+5\\\\h=61.25\ m

So, the maximum height reached by the ball is 61.25 m.

8 0
3 years ago
A, b, c, and d please
DIA [1.3K]
<h2>Answers / Step-by-step explanation:</h2><h3>a. What is the length of one side of the square.</h3>

<em>Looking at the image, the radius (r) of the circle appears to cover half of the length of a side of the square. Hence, the side of the square has a length of </em><em>2r</em><em>.</em>

<em />

<u><em>-------------------------------------------------------------------------------------------------------</em></u>

<em />

<h3>b. The formula A= πr² is used to find the area of a circle. The formula A=4r² can be used to find the area of the square. Write the ratio of the area of the circle to the area of the square in the simplest form.</h3>

<em />Ratio=\frac{\pi r^{2} }{4r^2} =\frac{\pi}{4}.

<em>Notice that the value "r²" disappears from the expression because is being multiplied and divided by it at the same time.</em>

<em />

Ratio=\frac{4\pi }{16} =0.7854.

<em />

<u><em>-------------------------------------------------------------------------------------------------------</em></u>

<em />

c. Complete the table.

<em>To complete each cell of the table, simply take the equation of the asked parameter and substitute the value of r by the number indicated in the title of the column. For example, column 3 should be filled out like this:</em>

Area of Circle (units²): π(3)²or 9π.

Length of 1 Side of the Square: 2r= 2(3)= 6.

Area of Square (units²)= 4r²= 4(3)²= 36.

Ratio: \frac{\pi}{4}.

<em>Do the same for all the other columns. </em>

<em>The answers to the table are presented on the attached image</em><em>.</em>

<em />

<u><em>-------------------------------------------------------------------------------------------------------</em></u>

<em />

d. What can you conclude about the relationship between the area of the circle and the square?

<em>They will always have the same value, π/4, regardless of the size of the square and circle. As long as the circle borders meet the square's at the middle of each side of the square, the relationship will be the same</em><em>.</em>

4 0
2 years ago
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