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2 years ago

Task 3&4, please with the formula

Computers and Technology

1 answer:

Anastasy [175]2 years ago

6 0

It’s 12 because 3 times 4 is twelve, hope i helped!

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Write a program that prompts the user for two numbers then outputs the result of dividing the first number by the second number

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The program is

num = int(input("Enter Numerator "))

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Perl code

use strict;

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2 years ago

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Please help guys I'm so lost

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The correct answer is C ( W * 5 )

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3. The wildlife department has been feeding a special food to rainbow trout finger lings in a pond. A sample of the weight of 40

andrey2020 [161]

Answer:

1) 402.7 grams. This estimate is called the sample mean.

2) (399.11, 406.29)

3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.

I am 99% sure that the value lies between 399.11 grams and 406.29 grams.

Explanation:

sample size (n) = 40, the mean weight (x)= 402.7 grams and the standard deviation (σ)=8.8 grams

1) The point estimated mean weight of the population is 402.7 grams. This estimate is called the sample mean.

2) c = 99% = 0.99

α = 1 - 0.99 = 0.01

$\frac{\alpha }{2} =\frac{0.01}{2} =0.005$ .

The z score of 0.005 corresponds with the z score of 0.495 (0.5 - 0.005).

$z_\frac{\alpha }{2} =2.58$ .

The margin of error (e) = $z_\frac{\alpha }{2}*\frac{\sigma}{\sqrt{n} } =2.58*\frac{8.8}{\sqrt{40} } =3.59$

The confidence interval = x ± e = 402.7 ± 3.59 = (399.11, 406.29)

3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.

I am 99% sure that the value lies between 399.11 grams and 406.29 grams.

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3 years ago