It is safe to use your bright headlights if there is a car ahead of you within 300 feet
2 answers:
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Answer:
Following are the code to this question:
//import package
import java.util.*;
public class Full_XmasTree //defining class
{
// defining main method
public static void main(String as[])
{
int X,a,b; //defining integer variable
Scanner obx = new Scanner(System.in); // creating Scanner class object
System.out.print("Please enter: "); //print message
X = obx.nextInt(); // input value from user
for (a = 0; a < X; a++) //defining loop to print pattern
{
for (b = X - a; b > 1; b--)//use loop for print white space
{
System.out.print(" ");//print space
}
for (b = 0; b <= a; b++) // use loop to print values
{
System.out.print("* "); //print asterisk values
}
System.out.println(); //using print method for new line
}
}
}
Output:
please find the attachment.
Explanation:
In the given java code, a class "Full_XmasTree" is declared, in which the main method is declared, inside this method three integer variable "X, a, and b", in this variables "a and b" is used in a loop, and variable X is used for user input.
- In the next line, the Scanner class object is created, which takes input in variable X, and for loop is used to print asterisk triangle.
- In the first for loop, use variable a to count from user input value, inside the loop, two for loop is used, in which first is used to print white space and second is used for the print pattern.
Solution :
#include
#include
#include
//Converts to binary string.
* hexadecimal
Binary(char* hexdec)
{
long = 0;
char *string = (sizeof(char) * 9);
while (hexdec[i]) {
//Simply assign binary string for each hex char.
switch (hexdec[i]) {
strcat(string, "0000");
break;
strcat(string, "0001");
break;
strcat(string, "0010");
break;
strcat(string, "0011");
break;
strcat(string, "0100");
break;
strcat(string, "0101");
break;
strcat(string, "0110");
break;
strcat(string, "0111");
break;
strcat(string, "1000");
break;
strcat(string, "1001");
break;
case 'A':
case 'a':
strcat(string, "1010");
break;
case 'B':
case 'b':
strcat(string, "1011");
break;
case 'C':
case 'c':
strcat(string, "1100");
break;
case 'D':
case 'd':
strcat(string, "1101");
break;
case 'E':
case 'e':
strcat(string, "1110");
break;
case 'F':
case 'f':
strcat(string, "1111");
break;
default:
printf("\nInvalid hexadecimal digit %c",
hexdec[i]);
string="-1" ;
}
i++;
}
return string;
}
int main()
{ //Take 2 strings
char *str1 =hexadecimalToBinary("FA") ;
char *str2 =hexadecimalToBinary("12") ;
//Input 2 numbers p and n.
int p,n;
scanf("%d",&p);
scanf("%d",&n);
//keep j as length of str2
int j=strlen(str2),i;
//Now replace n digits after p of str1
for(i=0;i<n;i++){
str1[p+i]=str2[j-1-i];
}
//Now, i have used c library strtol
long ans = strtol(str1, NULL, 2);
//print result.
printf("%lx",ans);
return 0;
}