Answer:
D. Wind turbines take up a lot of space.
Explanation:
In wind turbines the kinetic energy received by the air molecules is converted into electrical energy by the use of turbines
So here in order to get more kinetic energy from air we need more crossectional area of the wind mill to interact with the air
So here we need the large size of turbines
so this is the main disadvantage of the wind turbines because it needs large area to install the whole setup also the efficiency of this turbine is small so it needs large number of wind mills to setup good output power
so correct answer will be
D. Wind turbines take up a lot of space.
Answer:
tension is 37.8 N
Explanation:
given data
mass of bar m1 = 2 kg
length of bar L = 1.4 m
suspended mass m2 = 5 kg
suspended object position length L2 = 0.8 m
to find out
tension
solution
we consider here bar is connected with hinge and
we know here system is equilibrium
so here net torque will be zero at joint
and mass 2 kg act at L1 = 1.4 /2 = 0.7 m
so torque = m1×g× ( L1 ) + m2 ×g× (L2) - T(L)
so
2 ×9.8 × ( 1.4/2) + 5×9.8 × ( 0.8) - T(1.4) = 0
T = 52.98 / 1.4
T = 37.8
so tension is 37.8 N
Answer:
11 m/s
Explanation:
The motion of the box is a uniformly accelerated motion (=constant acceleration), therefore we can use the following suvat equation:
where:
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the box in this problem, we have:
u = 3 m/s is the initial velocity
is the acceleration
t = 4 s is the time interval
Solving for v, we find the velocity after 4 seconds:
Answer:
Relative to Carlos the Whataburger is moving at 0 speed.
Explanation:
Carlos speed, = 35 m/s
speed of another car, = -25 m/s
The speed of the Whataburger, = 35 m/s since it is in the same car as Carlos.
The relative of the Whataburger to Carlos is given as;
Therefore, Relative to Carlos the Whataburger is moving at 0 speed.
Answer:
The charge that flow through the calculator is 0.384 C
Explanation:
Given;
current drawn by the calculator, I = 0.0008 A
time of current flow, t = 8 min = 8min x 60s = 480 s
The charge that flow through the calculator is given;
q = It
where;
q is the charge that flow through the calculator
I is the current drawn
t is the time
q = 0.0008 x 480
q = 0.384 Coulombs
Therefore, the charge that flow through the calculator is 0.384 C