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Pachacha [2.7K]
4 years ago
10

A regulation basketball has a 22 cm di-

Physics
1 answer:
Solnce55 [7]4 years ago
4 0

Answer:

0.70 s

Explanation:

Potential energy = kinetic energy + rotational energy

mgh = ½ mv² + ½ Iω²

For a thin spherical shell, I = ⅔ mr².

mgh = ½ mv² + ½ (⅔ mr²) ω²

mgh = ½ mv² + ⅓ mr²ω²

For rolling without slipping, v = ωr.

mgh = ½ mv² + ⅓ mv²

mgh = ⅚ mv²

gh = ⅚ v²

v = √(1.2gh)

v = √(1.2 × 9.81 m/s² × 1.1 m sin 49.0°)

v = 3.13 m/s

The acceleration down the incline is constant, so given:

Δx = 1.1 m

v₀ = 0 m/s

v = 3.13 m/s

Find: t

Δx = ½ (v + v₀) t

t = 2Δx / (v + v₀)

t = 2 (1.1 m) / (3.13 m/s + 0 m/s)

t = 0.704 s

Rounding to two significant figures, it takes 0.70 seconds.

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6. You are in an airplane going down a runway currently going 24 m/s and accelerating at 8 m/s?
Allisa [31]

Answer:

The time taken by the airplane to take off, t = 11.46 s

Explanation:

Given data,

The initial velocity of the airplane, u = 24 m/s

The acceleration of the plane, a = 8 m/s

The distance covered until take off, d = 800 m

Using the III equation of motion,

                      v² = u² +2as

                           = 24² + 2 x 8 x 800

                           = 13376

                       v = 115.65 m/s

Using the first equation of motion,

                      v = u + at

                       t = (v-u) / a

                         = (115.65 - 24) / 8

                         = 11.46 s

Hence, the time taken by the airplane to take off, t = 11.46 s

4 0
3 years ago
A racecar driver on a flat racetrack steps on the gas, changing her velocity from 10 m/sec to 30 m/sec in 5 seconds. What is the
erastova [34]

Answer:

4m/s2

Explanation:

The following data were obtained from the question:

U (initial velocity) = 10m/s

V (final velocity) = 30m/s

t (time) = 5secs

a (acceleration) =?

Acceleration is the rate of change of velocity with time. It is represented mathematically as:

a = (V - U)/t

Now, with this equation i.e

a = (V - U)/t, we can calculate the acceleration of the race car as follow:

a = (V - U)/t

a = (30 - 10)/5

a = 20/5

a = 4m/s2

Therefore, the acceleration of the race car is 4m/s2

8 0
4 years ago
Read 2 more answers
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