An object with a mass of 2.0 kg accelerates 2.0 m/s2 when an unknown force is applied to it. What is the amount of the force?
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Answer:
Incomplete question, check attachment for the graph needed to solve problem.
A 8.1nm........
Explanation:
Electric Field is given as
E=V/d
Where V is voltage
And d is the distance apart
E is the electric field
The voltage V just before action of potential is -70mV,
The value d=8.1nm
d=8.1×10^-9m
E=V/d
E=-70×10^-3/8.1×10^-9
E=-8.6×10^6 N/C
Then the magnitude of the electric field is 8.6×10^6N/C
Two forces 3N and 4N act on a body in a direction due north From East, the equilibrant's angle is given by .
The equilibrium force is the balanced force when the net force acting is zero and is the exact opposite of the consequent force. The resultant force is one single force replaced by numerous forces.
<h3>Briefing:</h3>3N and 4N are the two forces pulling on a body.
The forces work along the North and the East, which are perpendicular to one another.
The resultant of the forces, which is provided by the equilibrant force,
R = √(3)²+(4)²
R = 5N
From East, the equilibrant's angle is given by
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