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NeTakaya
2 years ago
10

Find the value of 7⁴​

Mathematics
2 answers:
Mandarinka [93]2 years ago
7 0
I think 2401...I just asked Siri
nydimaria [60]2 years ago
5 0

Answer:

2401

Step-by-step explanation:

Because 7x7x7x7 is 2401, you’re supposed to multiply 7 by it’s exponent, and in this case, its 4. So multiply, 7 four times.

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Find the mean of the data
pogonyaev

108+103+98+105+85+112+119+82+94+115+126+89 = 1236

1236÷12 =103

4 0
3 years ago
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What is 0.17 as an equivalent fraction
xenn [34]
Since the 17 is in the hundreds place, the fraction would be 17/100. ☺️
8 0
3 years ago
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Estimate the rate of change of the graphed function over the interval -4 <_ x <_ 0
dezoksy [38]

Answer:

  0.2071

Step-by-step explanation:

It looks like the graph is of the function ...

  y = √(x +8) -2

We know that (-4, 0) is one point on the graph. The other point of interest is at x=0, where y = √8 -2 ≈ 0.8284.

The average rate of change on the interval is then ...

  m = (0.8284 -0)/(0 -(-4)) = 0.2071

The average rate of change on the interval is about 0.2071.

_____

<em>Rougher estimate</em>

The graph goes through the points (-4, 0) and (1, 1), so has a slope of 1/5 = 0.2 on the interval [-4, 1]. We know the graph does not go through (0, 1), so the slope is not as high as 1/4 = 0.25. The curve is concave downward, so the average slope will be higher than 0.2, but we aren't sure how much higher.

A reasonable estimate of the rate of change on the interval is "a little more than 0.2, but less than 0.25."

4 0
2 years ago
Find the slope of the line through (–9, –10) and (–2, –5). A. –five-sevenths B. seven-fifths C. five-sevenths D. –negative seven
vredina [299]

Answer:

C 5/7

Step-by-step explanation:

We can find the slope of a line using

m = (y2-y1)/(x2-x1)

   = (-5 - -10) /(-2 - -9)

   = (-5 +10)/(-2+9)

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8 0
3 years ago
The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) 5x/x^2
Olegator [25]

Given :

The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) = \dfrac{5x}{x^2+9}.

To Find :

Find the time at which the concentration is a maximum. b. Find the maximum concentration.

Solution :

For maximum value of x, K'(x) = 0.

K'(x) = \dfrac{5(x^2+9)- 5x(2x)}{(x^2+9)^2}=0\\\\5x^2+45-10x^2=0\\\\5x^2 = 45\\\\x = \pm 3

Since, time cannot be negative, so ignoring x = -3 .

Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6

Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.

Hence, this is the required solution.

5 0
2 years ago
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