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Marat540 [252]
2 years ago
15

What is the quotient and remainder of 2,913 divided by 6

Mathematics
1 answer:
shusha [124]2 years ago
5 0

Answer:

2913 divided by 6 is 485 with a remainder of 3

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EASY MATH GOOD POINTS
34kurt

Answer:

t = (D/C - 1) (100/r)

Step-by-step explanation:

D = C(1+rt/100)

D/C = 1 + rt/100

D/C - 1 = rt/100

D/C - 1 = t (r/100)

Therfore,

<h2>t = (D/C - 1) / r/100</h2>

Therefore the last option is correct.

<h2><em><u>PLEASE MARK MY ANSWER AS BRAINLIEST!!!!!</u></em></h2>
8 0
4 years ago
Read 2 more answers
Find a number so that 97.3% of it is 36
tiny-mole [99]
So x is the number
x time 97.3%=36
percent measn parts out of 100 so
97.3%=97.3/100=9.73/10=0.973/1=0.973
x times 0.973=36
divide both sides by 0.973
x=36.9989...
answer is aprox 36.9
7 0
3 years ago
I didn’t study and it’s 2 am pls help
AlexFokin [52]

Answer: 7. g = -50, 8. f= 340/6 9. 3 10 .125

Step-by-step explanation:#7 g(3): 4(3)^2 +6 =12^2 +6 = 1444=6= 150. We divide 150 by 3 giving us -50.  #8We start by putting f(6): -3(6)^2 -4(6) +8. We use PEMDAS. -18^2 -24 +8 = _324-24+8 F= 340/6 #9 g(15) = Square root of 15-6=9 and the square root of 9 is 3, therefore, the answer is 3. #10 h (x) = 2^x we plug -3 to 2^-3. It is a negative number and it gives us .125 or 12.5

3 0
3 years ago
Read 2 more answers
Can someone please help me with this question??
steposvetlana [31]

Answer:

450

Step-by-step explanation:

3*150 because the 150is your main number or otherwise known as "b" and then 3 is the multiplier so 3 * 150

6 0
3 years ago
Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. 6 sqrt 2
Gemiola [76]
Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.

There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
a = b = c \div  \sqrt{2} \\ c  = a\sqrt{2}  \\ c = 6 \sqrt{2} \times \sqrt{2}  = 6 \times 2 = 12
Another way to do it is the longer proof of Pythagorean Theorem:
{c}^{2}  =  {a}^{2}  +  {b}^{2}... \:  \:  c =   \sqrt{({a}^{2}  +  {b}^{2})}  \\
c= \sqrt{({6 \sqrt{2}) }^{2} + ({6 \sqrt{2})}^{2}}  \\ =  \sqrt{(2 \times{(6 \sqrt{2} )}^{2} )}  =  \sqrt{2(36 \times 2)}  \\ c =  \sqrt{144}  = 12

7 0
3 years ago
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