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4 years ago

A block has a mass of 30g and dimensions of 1.5cm by 4.8cm by 2.3 cm. Will the block float or sink in

Chemistry

1 answer:

zimovet [89]4 years ago

3 0

The block will sink

Explanation:

In general, an object with a higher density than water will sink in it, and one with a lower density will float. Now, to know if the block will float or sink, the first step is to calculate the density of the block, and to do this, the volume and mass of the block are required.

Mass of the block: 30 grames

Volume of the block:

The volume of the block is not provided, but this can be found using the dimensions given.

V (Volume) = s (side) x s x s

V = 1.5 cm x 4.8 cm x 2.3 cm

V = 16.56 $cm^{3}$

Density of the block:

To find the density simply divide the mass into the volume

D (density) = M (Mass) ÷ V (Volume)

D = 30 grams ÷ 16.56 $cm^{3}$

D = 1. 811 grams/ $cm^{3}$

The density of the block is 1. 811 grams/ $cm^{3}$

Additionally, the density of the water is 1 gram/ $cm^{3}$ or 1 gram/mL. According to this, the density of the block is higher than the density of the water, and therefore this is the block sinks.

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3 years ago

What is the concentration (M) of CH3OH in a solution prepared by dissolving 34.4 g of CH3OH in sufficient water to give exactly

bonufazy [111]

Answer:

4.67M

Explanation:

The concentration of methanol (CH3OH) can be calculated using the following:

Molarity (M) = number of moles(n)/volume(v)

However, mole is not given. It can be obtained by using:

Mole = mass / molar mass

Where; mass = 34.4g

Molar mass (MM) of CH3OH is:

= 12 + 1(3) + 16 + 1

= 12 + 3 + 17

= 32g/mol

mole = 34.4/32

mole = 1.075mol

The volume needs to be converted to L by dividing by 1000

230mL = 230/1000

= 0.230L

Molarity = mol/volume

Molarity = 1.075/0.230

Molarity = 4.6739

Molarity = 4.67M

The concentration of CH3OH in solution is 4.67M

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3 years ago

in order to find the molar mass of an unknown compound, a research scientist prepared a solution of 0.930 g of an unknown in 125

PtichkaEL [24]

Answer:

Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

Explanation:

Let's apply the formula for freezing point depression:

ΔT = Kf . m

ΔT = 74.2°C - 73.4°C → 0.8°C

Difference between the freezing T° of pure solvent and freezing T° of solution

Kf = Cryoscopic constant → 5.5°C/m

So, if we replace in the formula

ΔT = Kf . m → ΔT / Kf = m

0.8°C / 5.5 m/°C = m → 0.0516 mol/kg

These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg

0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:

Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

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