The block will sink
Explanation:
In general, an object with a higher density than water will sink in it, and one with a lower density will float. Now, to know if the block will float or sink, the first step is to calculate the density of the block, and to do this, the volume and mass of the block are required.
Mass of the block: 30 grames
Volume of the block:
The volume of the block is not provided, but this can be found using the dimensions given.
V (Volume) = s (side) x s x s
V = 1.5 cm x 4.8 cm x 2.3 cm
V = 16.56
Density of the block:
To find the density simply divide the mass into the volume
D (density) = M (Mass) ÷ V (Volume)
D = 30 grams ÷ 16.56
D = 1. 811 grams/
The density of the block is 1. 811 grams/
Additionally, the density of the water is 1 gram/ or 1 gram/mL. According to this, the density of the block is higher than the density of the water, and therefore this is the block sinks.
Answer:
Explanation:
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In this case, according to the described chemical reaction, Cl2 replaces iodine in NaI in order to produce I2 and NaCl:
It is possible to realize how chlorine replaces iodine in agreement with the single displacement reaction. Moreover, since chlorine and iodine atoms are not correctly balanced, we add a 2 in front of both NaI and NaCl in order to do so:
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The most reactive metal on the periodic table is Francium, However, Francium is an artificial element and only minimal quantities have been produced, so for all practical purposes, the most reactive metal available is Cesium, in the alkali metal family.
ANSWER In theory, Francium, in practice the Cesium
Answer:
1. pH = 1.23.
2.
Explanation:
Hello!
1. In this case, for the ionization of H2C2O4, we can write:
It means, that if it is forming a buffer solution with its conjugate base in the form of KHC2O4, we can compute the pH based on the Henderson-Hasselbach equation:
Whereas the pKa is:
The concentration of the base is 0.347 M and the concentration of the acid is 0.347 M as well, as seen on the statement; thus, the pH is:
2. Now, since the addition of KOH directly consumes 0.070 moles of acid, we can compute the remaining moles as follows:
It means that the acid remains in excess yet more base is yielded due to the effect of the OH ions provided by the KOH; therefore, the undergone chemical reaction is:
Which is also shown in net ionic notation.
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