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Sergio039 [100]
3 years ago
6

Mercury is an element. Which of the following would be the same for all atoms of mercury?

Chemistry
2 answers:
Flura [38]3 years ago
8 0

The number of protons

for all atoms of mercury will remain the same while different isotopes may have different number of neutrons.

Explanation:

Atoms should have equal numbers of protons and electrons. In our example, an atom of thirty six|chemical element, it should contain thirty six electrons since it contains 36 protons. Electrons are organized around atoms in a very special method.

ycow [4]3 years ago
6 0

Answer:

The number of protons

for all atoms of mercury will remain the same while different isotopes may have different number of neutrons.

Explanation:

Atoms should have equal numbers of protons and electrons. In our example, an atom of thirty six|chemical element, it should contain thirty six electrons since it contains 36 protons. Electrons are organized around atoms in a very special method

Read more on Brainly.com - brainly.com/question/964897#readmore

Explanation:

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In the sun, hydrogen is converted to ____________________ through nuclear fusion.
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Answer:

Helium

In the sun, hydrogen is converted to __<u>Helium</u>__ through nuclear fusion.

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3 years ago
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What is the formula of the salt produced by this reaction?
SpyIntel [72]
The answer is d cuz it’s doesn’t make a lot of the formula
7 0
3 years ago
The work function of palladium (Pd) is 5.22 eV. What is the minimum frequency of light to observe the photoelectric effect from
Ivan

Answer:

1)4×10^13Hz

2) 9.95×10-9J

Explanation:

From the image attached, it is clear that the work function of the palladium metal must first be obtained in joules. Then, the frequency is obtained from E=hf.

The kinetic energy if the photoelectrons is obtained as the difference between the energy of the photon and the work function of the metal.

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3 years ago
What element/compounds are used in the melting of ice?
Galina-37 [17]

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8 0
4 years ago
Calculate the pH during the titration of 30.00 mL of 0.1000 M HCOOH(aq) with 0.1000 M NaOH(aq) after 29.3 mL of the base have be
pashok25 [27]

Answer:

3.336.

Explanation:

<em>Herein, the no. of millimoles of the acid (HCOOH) is more than that of the base (NaOH).</em>

<em />

So, <em>concentration of excess acid = [(NV)acid - (NV)base]/V total</em> = [(30.0 mL)(0.1 M) - (29.3 mL)(0.1 M)]/(59.3 mL) = <em>1.18 x 10⁻³ M.</em>

<em></em>

<em> For weak acids; [H⁺] = √Ka.C</em> = √(1.8 x 10⁻⁴)(1.18 x 10⁻³ M) = <em>4.61 x 10⁻⁴ M.</em>

∵ pH = - log[H⁺].

<em>∴ pH = - log(4.61 x 10⁻⁴) = 3.336.</em>

7 0
3 years ago
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