Answer:
%
%
%
%
Explanation:
If we know the grams of a chemical compound in a specific reaction, it is possible to know the percentage of each atom that composes it.
For the Aluminum Oxide in this problem, we know its total weight and the grams of each component.
therefore we can determine the percentage ratio of its components through:
For Al
%
%
% 
%
%%
In the same way for oxygen
%
%
%
%
%%
Given the percentage composition of HC as C → 81.82 % and H → 18.18 %
So the ratio of number if atoms of C and H in its molecule can will be:
C : H = 81.82 12 : 18.18 1 C : H = 6.82 : 18.18 = 6.82 6.82 : 18.18 6.82 = 1 : 2.66 ≈ 3 : 8
So the Empirical Formula of hydrocarbon is:
C 3 H 8
As the mass of one litre of hydrocarbon is same as that of C O 2 The molar mass of the HC will be same as that of C O 2 i.e 44 g mol
Now let Molecular formula of the HC be ( C 3 H 8 ) n
Using molar mass of C and H the molar mass of the HC from its molecular formula is:
( 3 × 12 + 8 × 1 ) n = 44 n So 44 n = 44 ⇒ n = 1
Hence the molecular formula of HC is C 3 H 8
Does that help?
Answer:
Volume would be 13
Explanation:
Divide the mass by the density
65/5
Answer:
See Explanation
Explanation:
Wind is a renewable source of energy widely used as a source of energy in order to minimize the pollution that results from some other sources of non renewable energy.
Wind energy has the advantage of;
1) being a renewable source of energy hence it can be reused and it is not easily depleted.
2) it does not lead to any form of environmental pollution.
On the other hand, a lot of space is required in order to mount as many windmills as possible in order to generate enough electricity to serve a large area. Thus, the disadvantages of wind energy are;
1) A large expanse of land is required in order to generate a meaningful quantity of energy.
2) The occurrence of wind is inconsistent hence generation of energy is not steady.
Definitions needed:
pH = -log[H^+]
pOH = -log[OH^-]
pH + pOH = 14
[H^+]*[OH^-] = 10^-14
(a) [H+] = 3.0 10-13 M
[OH ‾ ] = _____ M
Acidic, Basic, or Neutral?
[H^+]*[OH^-] = 10^-14
[OH^-] = (10^-14)/[H^+]
[OH^-] = (10^-14)/(3.0 10-13 M) = 0.033 M
That's a high concentration of [OH^-], so the solution is basic
(b) [OH ‾ ] = 3.0 10-7 M
[H+] = ______M
Acidic, Basic, or Neutral?
[H^+]*[OH^-] = 10^-14
[H^+]* = (10^-14)/[OH^-]
[H^+]* = (10^-14)/(3.0 10-7 M) = 3.33 x 10^-8
That would be a slightly basic solution (pH just higher than 7).
