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borishaifa [10]
2 years ago
12

Figure A is a scale image of Figure B. What is the value of x?

Mathematics
1 answer:
kari74 [83]2 years ago
8 0
The value of x is 72

Each side increased by 20%
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What is the value of x in the equation shown? 2(X + 8) - 4x = 10x + 4
Anna007 [38]

Answer:

Option C: X=1

Step-by-step explanation:

2(X + 8) - 4x = 10x + 4

2X + 16- 4X= 10X + 4

-2X +16 =10X + 4

16 - 4 = 10X+2X

12 =12X

X=1

7 0
2 years ago
Factorise completely<br> 12x4yz2−8x3y3z2
Lina20 [59]
Final result :

4x3yz2 • (3x - 2y2)
Reformatting the input :

Changes made to your input should not affect the solution:

(1): "z2" was replaced by "z^2". 4 more similar replacement(s).

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((12•(x4))•y)•(z2))-((23x3•y3)•z2)
Step 2 :

Equation at the end of step 2 :

(((22•3x4) • y) • z2) - 23x3y3z2
8 0
3 years ago
Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0
Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0

The general equation for the second-order polynomial is:

x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}

This condition must be observed for the case of a quadratic equation with equal roots:

4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0

k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0

k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0

3\cdot k^{3} - 3\cdot k - 1 = 0

7 0
3 years ago
LOTS OF POINTS PLEASE ANSWER <br><br> angle a and c are supplementary or congruent??
Dmitry_Shevchenko [17]

Answer:

Supplementary

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Plzzzz, HELP ME!!! NOW
Lina20 [59]
Yea i think its step 2
3 0
3 years ago
Read 2 more answers
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