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coldgirl [10]
2 years ago
12

Which statement correctly names the congruent triangles and justifies the reason for congruence?

Mathematics
2 answers:
Marat540 [252]2 years ago
8 0

Answer:

  C. Triangle BAC is congruent to triangle FDE by AAS

Step-by-step explanation:

BAC names the vertices in the order longest-side, shortest-side. That same order is FDE in the other triangle, eliminating choiced B and D. The triangles are not right triangles, eliminating choice A.

The only viable answer choice is C.

No specific sides are shown as being congruent, but two angles are, so we could claim congruence by ASA or AAS. Answer choice C uses the latter.

goblinko [34]2 years ago
6 0

Answer:

ΔBAC ≅ ΔFDE by AAS

Step-by-step explanation:

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5 0
3 years ago
The graph represents the function (check picture)
Taya2010 [7]

Answer:

a = 1 and b = -12

Step-by-step explanation:

* Lets look to the graph to solve the problem

- f(x) is a rational function with:

# numerator ⇒ x² - 4x + 3

# denominator ⇒ x² + ax + b

- To find the values of a and b lets use the hole and the vertical

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∵ There is a hole at x = 3

- The hole appears when the numerator and the denominator have

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∵ x = 3 ⇒ subtract 3 from both sides

∴ x - 3 = 0

∴ The numerator and the denominator have a factor (x - 3)

- The vertical asymptotes appear at the zeros of the denominator

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∵ There is a vertical asymptote at x = -4

∵ x = -4 ⇒ add 4 for both sides

∴ x + 4 = 0

∴ The denominator has another factor (x + 4)

- The denominator x² + ax + b has two factors (x - 3) and (x + 4) lets

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∵ (x - 3)(x + 4) = (x)(x) + (x)(4) + (-3)(x) +(-3)(4)

∴ (x - 3)(x + 4) = x² + 4x - 3x - 12 = x² + x - 12

∴ x² + ax + b = x² + x - 12

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∴ a = 1 and b = -12

8 0
3 years ago
What is the sum? 3k/k^2+k-7/4K
Aleksandr-060686 [28]

Answer:

  \dfrac{k^2+5k}{4k^2}

Step-by-step explanation:

A suitable common denominator is 4k^2. (This eliminates the first and last choices.)

\dfrac{3k}{k^2}+\dfrac{k-7}{4k}=\dfrac{4(3k)}{4(k^2)}+\dfrac{k(k-7)}{k(4k)}\\\\=\dfrac{12k+k^2-7k}{4k^2}=\boxed{\dfrac{k^2+5k}{4k^2}}

3 0
3 years ago
Do you know what the answer to this question is?
Y_Kistochka [10]

I think the answer is 4

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3 years ago
Which of the following statements are true about the graph below? Select all that apply
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I don’t know because it wouldn’t pop up
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