Which statement correctly names the congruent triangles and justifies the reason for congruence?

Mathematics

2 answers:

Marat540 [252]2 years ago

8 0

Answer:

C. Triangle BAC is congruent to triangle FDE by AAS

Step-by-step explanation:

BAC names the vertices in the order longest-side, shortest-side. That same order is FDE in the other triangle, eliminating choiced B and D. The triangles are not right triangles, eliminating choice A.

The only viable answer choice is C.

No specific sides are shown as being congruent, but two angles are, so we could claim congruence by ASA or AAS. Answer choice C uses the latter.

goblinko [34]2 years ago

6 0

Answer:

ΔBAC ≅ ΔFDE by AAS

Step-by-step explanation:

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Find the zeroes of the following equation:

weqwewe [10]

Answer: $\bold{x=\dfrac{1\pm \sqrt5}{2}}$

both zeros are irrational numbers

Step-by-step explanation:

Note: The question would have made more sense if if it was 2/x = x - 1 but I will answer it as written.

$\dfrac{1}{x}=x-1\qquad \text{Restriction: }x\neq 0\\\\\\\text{Cross multiply, simplify, and set equal to zero:}\\1=x(x-1)\\\\1=x^2-x\\\\0=x^2-x-1\\\\\\\text{This is not factorable so you will need to use Quadratic Formula:}\\\\x=\dfrac{-(-1)\pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}\\\\\\x=\dfrac{1\pm \sqrt5}{2}$